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3 years ago

What is the complete ionic equation for H2SO4(aq) + Cal2(aq) -> CaSO4(s) + 2HI(aq)?

2 answers:

6 0

2H(+) + SO4(2-) + Ca(2+) + 2I(-) -> CaSO4(s) + 2H(+) + 2I(-)
The signs in brackets are the subscripts for the charge of the ion. This is the complete ionic equation. The net ionic equation is:
Ca(2+) + SO4(2-) -> CaSO4

Leokris [45]3 years ago

4 0

Answer:

SO₄²⁻(aq) + Ca²⁺(aq) → CaSO₄(s)

Explanation:

Given equation:

H₂SO₄(aq) + Cal₂(aq) → CaSO₄(s) + 2HI(aq)

Ionic equation:

2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺ (aq) + 2I⁻(aq)

Net ionic equation:

SO₄²⁻(aq) + Ca²⁺(aq) → CaSO₄(s)

2H⁺ (aq) and 2I⁻(aq) ions are common on both side of the equation hence they were eliminated. (aq) here means that the ions are in aqueous phase and (s) means solid or precipitate. CaSO₄ forms a white precipitate which does not ionize in the aqueous phase.

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At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressur

fenix001 [56]

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.

<h3>What is Henry's Law ?</h3>

Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.

<h3>What is relationship between Henry's Law constant and Solubility ?</h3>

The solubility of gas is directly proportional to partial pressure.

It is expressed as:

$S_{\text{gas}} = K_{H} P_{\text{gas}}$

where,

$S_{\text{gas}}$ = Solubility of gas

$K_{H}$ = Henry's Law constant

$P_{\text{gas}}$ = Partial pressure of gas

Now put the values in above expression we get

$S_{\text{gas}} = K_{H} P_{\text{gas}}$

0.080M = $K_{H}$ × 1.7 atm

$K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}$

= 0.047 M/atm

Now we have to find the partial pressure of He

$S_{\text{gas}} = K_{H} P_{\text{gas}}$

0.200 M = 0.047 M/atm × $P_{\text{gas}}$

$P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}$

= 4.25 atm

Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.

Learn more about the Henry's Law here: brainly.com/question/23204201

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