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marissa [1.9K]
3 years ago
9

Which ofnthe following shows the correct use of distributive property when solving 1/3(33-x)=135,2

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer: OPTION C.

Step-by-step explanation:

The missing options are:

A. (33 - x) = \frac{1}{3} * 135.2\\\\B. (\frac{1}{3} *33) - \frac{1}{3} x = \frac{1}{3} * 135.2\\\\C.(\frac{1}{3}  * 33) - \frac{1}{3} x = 135.2\\\\D. (\frac{1}{3}  * 33) + \frac{1}{3} x = 135.2

In order to solve this exercise you need to remember the following:

1. The Distributive property states that:

a(b+c)=ab+ac\\\\a(b-c)=ab-ac

2. The multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

In this case the exercise gives you the following equation:

\frac{1}{3}(33-x)=135.2

Since you need to solve for the variable "x" in order to  find its value, the first  step you must apply in the in the procedure is to eliminate the parentheses applying the Distributive property.

Then, you must multiply everyting inside the parentheses by \frac{1}{3}.

Therefore,based on the explanation, you know that the correct use of the Distributive property is:

\frac{1}{3}*33-\frac{1}{3}x=135.2

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Lisa wants to use her calculator to square a two-digit positive integer, but she accidentally enters the tens digit incorrectly.
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Answer: Correct two digit number= 24

Step-by-step explanation:

Let

x= tens digit (wrong one)

and y= zeroes digit

and z= tens digit (right one)

Now according to the statement,

(10x+y)² -  (10z+y)² = 2340

Simplifying this we get

(x-z)(5x+y+5z)= 117= 1 * 3 * 3 * 13

So it could either be

x-z=1 or x-z=3

If we take the x-z=1

then 5x+y+5z=117

which is not possible as maximum value we can get from this is 99.

This leaves us with x-z=3

so 5x+y+5z= 39

Put x=3+z

We get,

y+10z= 24

Now as y and z both are single digits so the only possible numbers to fit these are y=4 and z=2.

Put z=2 in x=3+z , we get x=5

So the numbers become 10x+y= 54

and 10z+y= 24

Their sum is 54+24=78

Check

54²-24²= 2340 so it is correct.

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3 years ago
How many solutions does this system of equations have?
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Answer:

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Step-by-step explanation:

Hello there,

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