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sasho [114]
3 years ago
10

if something starts out at costing $500, and then is marked down by 25% on each of three occasions, what is the final price?

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0
Well first you multiply 500 by 25%, and you get 125, then you subtract 125 from 500, and you get, 375. Then you just do the same thing two more times, and you get 210.94.
Afina-wow [57]3 years ago
5 0
$125 because when you do $500x0.75 it equals $375. $500-375=$125
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It would be A. or B

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4 0
2 years ago
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What is the approximate value of q in the equation below?
gayaneshka [121]

<u>Given</u>:

The given equation is q+\log _{2}(6)=2 q+2

We need to determine the approximate value of q.

<u>Value of q:</u>

To determine the value of q, let us solve the equation for q.

Hence, Subtracting \log _{2}(6) on both sides of the equation, we get;

q=2 q+2-\log _{2}(6)

Subtracting both sides of the equation by 2q, we have;

-q=2-\log _{2}(6)

Dividing both sides of the equation by -1, we have;

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Now, substituting the value of log_2(6)=2.585, we have;

q=2.585-2

Subtracting the values, we get;

q=0.585

Thus, the approximate value of q is 0.585

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5 0
3 years ago
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Find the right quotient. 36m 5 n 5 ÷ (12m 3)
polet [3.4K]
ANSWER

The right quotient is

3  {m}^{2} {n}^{5}

EXPLANATION


The given expression is :

\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  \frac{36}{12}  \times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3\times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


Recall that,


\frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}
We apply this property to obtain;



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3 \times   {m}^{5 - 3}  \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3  {m}^{2} {n}^{5}

5 0
2 years ago
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6 0
3 years ago
I need some help with this
Ivenika [448]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
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