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3 years ago

The vertex of the parabola below is at the point (1.-3). Which of the equations below could be the one for this parabola?

Mathematics

2 answers:

Anon25 [30]3 years ago

5 0

Answer:

answer is choice D

Step-by-step explanation:

Apex

Ilia_Sergeevich [38]3 years ago

3 0

Answer: Choice D. y = (x-1)^2 - 3

The vertex is (h,k) = (1,-3). So h = 1 and k = -3.

We have a = 1 as the leading coefficient.

Plug those values into the equation below

y = a(x-h)^2 + k

y = 1(x - 1)^2 + (-3)

y = (x - 1)^2 - 3

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3 years ago

Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare

leva [86]

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Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is $y=3x$ , then its slope = 3 [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

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Equation of line with slope n and passers through (a,b) is

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Hence, Required equation : $x+3y=12$

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3 years ago

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boyakko [2]

Answer:

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3 years ago

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<h2>Hello my friend.</h2>

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<h2>I hope I have helped a lot.</h2>

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