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3 years ago

Can someone help me with this homework?

Mathematics

2 answers:

bazaltina [42]3 years ago

7 0

Answer:

(-4,-1)

Step-by-step explanation:

when you translate it by 3 units up, it becomes (-4,-1). and when you reflect over the x axis, it becomes (-4,-1)

Gemiola [76]3 years ago

5 0

Answer: (-4, -1)

Step-by-step explanation:

Starting at point (-4, -2) and translating 3 units up means we add 3 to -2.

So the new point is now (-4, 1).

Now we reflect over the x-axis which means the y-value of 1 becomes negative.

So the final point is (-4, -1)

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Lunna [17]

Answer:

y = 9.6

Step-by-step explanation:

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3 years ago

Simplify each expression using an exponent rule learned in class. <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7By%7D%7Bx%7D%20%

Maksim231197 [3]

Hey there! I'm happy to help!

If you raise a fraction to an exponent, you apply that exponent to the numerator and the denominator. This would give us $\frac{y^4}{x^4}$ .

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3 years ago

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Help? I’m in need of a answer with all the work shown. Someone? Anyone? Help me plz

Svetach [21]

Hello!

I will make approximations below to the nearest whole number

A. 2√32≈11

B. 5+√18≈9

C. √24≈5

D. √52-3≈4

E. 3√14≈11

F. √20+√26≈10

Based off of what we see here our even numbers are $\boxed {D}$ and $\boxed {F}$ .

I hope this helps!

4 0

3 years ago

[[3+ (8-3^2)-2] +3] / 5-2•2

katovenus [111]

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8
−
3
2
−
2
+
3
5
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(
2
)
(
2
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=
−
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6 0

3 years ago

Let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes. If the random var

jeka57 [31]

Answer:

The parameters of this exponential distribution is $\lambda$ = $\frac{1}{27}$ .

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes.

So, X = time it takes for a person to choose a birthday gift

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as average value of 27 minutes that means $\lambda = \frac{1}{27}$ .

So, X ~ Exp( $\lambda = \frac{1}{27}$ ) .

Therefore, the parameter of this exponential distribution is $\lambda$ .

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4 years ago