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lozanna [386]
3 years ago
12

E the location for each of the following staring points andlocation changes6. (5.3), 67- 8.5.3

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0
You have to to take the whole paper so i can able understand
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Assume that the growth rate of a population of ants is proportional to the size of the population at each instant of time. Suppo
Nutka1998 [239]
(1/A)  dA/dt=  C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
7 0
3 years ago
In the figure, the measure of angle 9 is 80 degrees and the measure of angle 5 is 68. Find the measure of each angle.
murzikaleks [220]

Answer/Step-by-step explanation:

Given:

m<9 = 80°,

m<5 = 68°

Lines w and v are parallel to each other.

m<1 = m<9 (corresponding angles theorem)

m<1 = 80°

m<2 + m<1 = 180° (linear pair)

m<2 + 80° = 180° (substitution)

m<2 = 180° - 80°

m<2 = 100°

m<3 = m<1 (vertical angles are congruent)

m<3 = 80°

m<4 = m<2 (vertical angles are congruent)

m<4 = 100°

m<6 + m<5 = 180° (linear pair)

m<6 + 68° = 180° (substitution)

m<6 = 180° - 68°

m<6 = 112°

m<7 = m<5 (vertical angles)

m<7 = 68°

m<8 = m<6 (vertical angles)

m<8 = 112°

m<10 = m<2 (corresponding angles)

m<10 = 100°

m<11 = m<9 (vertical angles)

m<7 = 80°

m<12 = m<10 (vertical angles)

m<12 = 100°

m<13 = m<5 (corresponding angles)

m<13 = 68°

m<14 = m<6 (corresponding angles)

m<14 = 112°

m<15 = m<13 (vertical angles)

m<15 = 68°

m<16 = m<14 (vertical angles)

m<16 = 112°

6 0
3 years ago
Hi can you please help me with my work​
babymother [125]
Hi yes I can:)
Its the first option. 3 1/2
5 0
3 years ago
Read 2 more answers
Nathan bought a cd for his friend. The length and width of the cd case is 4 18⁄25 inches. What is the area of the cd case?
ale4655 [162]

Answer:

Hence the area of CD bought by Nathan is <em>22.2784 square inches.</em>

Step-by-step explanation:

The length and width of a CD bought by Nathan is 4\frac{18}{25}=\dfrac{118}{25} inches.

As CD have the same length and width this means it will be of the shape of a square.

Hence, the area of CD is given by:

Area of CD=length×width

                 = 4\dfrac{18}{25}\times4\dfrac{18}{25}

                 =\dfrac{118}{25}\times\dfrac{118}{25}

                 =\dfrac{118\times118}{25\times25}

                 =\dfrac{13924}{625}

                 =22.2784

Hence the area of CD bought by Nathan is 22.2784 square inches.


3 0
3 years ago
Please answer the question! It is optional to answer the one where you need to upload the graph but if you wanna help answer it
Ganezh [65]
The answer is option 3
6 0
3 years ago
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