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3 years ago

Is 12 x -7 positive or negative

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

Hi! I'm not sure if I'm doing your question correctly, but 12×(-7)= -84.

so, if this is what you meant, it would be negative

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The distribution of heights of adult American men is approximately Normal with mean 69 inches and standard deviation 2.5 inches.

nalin [4]

Answer:

option C 13.5%

Step-by-step explanation:

As the heights of adults is normally distributed with mean=69 and standard deviation=2.5 so, the percent of men that are between 64 and 66.5 inches tall can be calculated as

P(64<X<66.5)=P[ (64-69)/2.5<(X-μ)/σ<(66.5-69)/2.5]

P(64<X<66.5)=P(-2<Z<-1)

P(64<X<66.5)=P(-2<Z<0)-P(-1<Z<0)

P(64<X<66.5)=0.4772-0.3413=0.1359

Thus, the percent of men are between 64 and 66.5 inches tall is 13.59%.

If we round the resultant quantity then it will be rounded to 13.6% but considering the given options, option C is most appropriate.

5 0

4 years ago

Given u = (2, -8) and v = (8, -2), what is u times v?

jolli1 [7]

Answer:

$u\cdot v=32$

Step-by-step explanation:

Assuming $u$ and $v$ are vectors, their dot product is $u\cdot v$ where $u_1v_1 + u_2v_2$ :

$u\cdot v=u_1v_1+u_2v_2=(2)(8)+(-8)(-2)=16+16=32$

Therefore, $u\cdot v=32$

3 0

3 years ago

A person bikes 2

Lerok [7]

Answer:

The person bikes 20 miles in an hour

Step-by-step explanation:

5 0

2 years ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago

Caroline has a collection of 280 coins. How many coins represent 5% of her collection?

Nataly [62]

Answer:

14 coins

Step-by-step explanation:

280 * 0.05 = 14

5 0

3 years ago