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OLEGan [10]
2 years ago
5

Help please!!! Everything is in the picture.

Mathematics
1 answer:
Valentin [98]2 years ago
7 0

Answer:

3u-2v = \sqrt{505\\}

5u-v = \sqrt{1,157}

2u-3v = \sqrt{1,300}

u+4v = \sqrt{4,505}

Step-by-step explanation:

I just started by doing the results for each of the operations given.

<u>3u-2v:</u>

3u = (-9, 24)       2v = (-28, 12)

Do the operation of 3u-2v and you get a resultant vector of (19, 12).

You calculate this by doing the square root of 19^2 + 12^2, which is the square root of 505.

<u>5u-v:</u>

5u = (-15, 40)       v = (-14, 6)

Do the operation of 5u-v and you get a resultant vector of (-1, 34).

You calculate this by doing the square root of (-1)^2 + 34^2, which is the square root of 1,157.

<u>2u-3v:</u>

2u = (-6, 16)   3v = (-42, 18)

Do the operation of 2u-3v and you get a resultant vector of (36, -2).

You calculate this by doing the square root of 36^2 + (-2)^2, which is the square root of 1,300.

<u>3u+2v:</u>

3u = (-9, 24)       2v = (-28, 12)

Do the operation of 3u+2v and you get a resultant vector of (-37, 36).

You calculate this by doing the square root of (-37)^2 + 36^2, which is the square root of 2,665. This is not a given tile, so we can just ignore this one.

<u>u+4v:</u>

u = (-3, 8)       4v = (-56, 24)

Do the operation of u+4v and you get a resultant vector of (-59, 32).

You calculate this by doing the square root of (-59)^2 + 32^2, which is the square root of 4,505.

Since this is a given tile, I didn't do 7u-2v, but you would use the same methodology.

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