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schepotkina [342]
3 years ago
7

Write the radical expression 8/^7√x^15 in exponential form

Mathematics
2 answers:
KonstantinChe [14]3 years ago
7 0

Answer:

8 \cdot x^{-\frac{15}{7}}

Step-by-step explanation:

Using exponent rule:

  • \sqrt[n]{a^m} = a^{\frac{m}{n}}
  • a^{-m}=\frac{1}{a^m}

Given the radical expression:

\frac{8}{\sqrt[7]{x^{15}} }

Apply the exponent rule:

\frac{8}{x^{\frac{15}{7}} }

Again apply the exponent rule:

8 \cdot x^{-\frac{15}{7}}

Therefore, the radical expression \frac{8}{\sqrt[7]{x^{15}} } in exponential form is, 8 \cdot x^{-\frac{15}{7}}

Gekata [30.6K]3 years ago
6 0
Rembber
\sqrt[n]{x^m}=x^\frac{m}{n}
and \frac{1}{x^m}=x^{-m} so

\frac{8}{ \sqrt[7]{x^{15}} }= \frac{8}{x^ \frac{15}{7} }=8x^{(\frac{-15}{7})}
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4 0
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Give an example of a point that is the same distance from (3, 0) as it is from (7, 0). Find lots of examples. Describe the confi
Artist 52 [7]

Supposse that the distance from the point (x,y) to the point (3,0) is equal to the distance from  (x,y) to the point (7,0). Then, by the formula of the distnace we must have

\sqrt{(x-3)^2 + (y-0)^2}=\sqrt{(x-7)^2 + (y-0)^2}

cancel the square root and the (y-0)^2's, and then expand the parenthesis to obtain

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then, simplifying we obtain

8x = 40

therfore we must have

x=5

this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: (5,0), (5,7),(5,1/2), (5,-10),.... The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.

3 0
3 years ago
- 6/39 simplified. :)​
stepan [7]

2/13_

Step-by-step explanation:

6/39_=

_6÷39/3

=2/39_

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4 0
1 year ago
I need help please ​
lisov135 [29]

Answer:

A. 1010 FT^3

Step-by-step explanation:

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3 years ago
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What is the equation of the line that passes through the point (-5,-2) and has a slope of -6/5
tatyana61 [14]

Answer:

The answer is

<h2>y =  -  \frac{6}{5} x - 8  \\</h2>

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1) \\

where

m is the slope

( x1 , y1) is the point

From the question the point is (-5,-2) and the slope is - 6/5

The equation of the line is

y + 2 =  -  \frac{6}{5} (x + 5) \\ y + 2  =  -  \frac{6}{5} x - 6 \\ y =  -  \frac{6}{5} x - 6 - 2

We have the final answer as

y =  -  \frac{6}{5} x - 8  \\

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5 0
3 years ago
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