Question

In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 28.54 mL of 0.2075 M NaOH is added to a 34.23 mL portion of H2SO4. What is the [H2SO4]?

Answer 1

            moles NaOH = c · V = 0.2075 mmol/mL · 28.54 mL = 5.92205 mmol
            moles H2SO4 = 5.92205 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.961025 mmol
Hence
            [H2SO4]= n/V = 2.961025 mmol / 34.23 mL = 0.08650 M
The answer to this question is  [H2SO4] = 0.08650 M