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KiRa [710]
3 years ago
13

To protect yourself from consuming too much _____, you should limit your consumption of swordfish, king mackerel, and shark. a.

arsenic b. mercury c. lead d. iron e. iodine
Chemistry
2 answers:
Serggg [28]3 years ago
5 0

Answer:

b. mercury

Explanation:

Fishes and some other sea foods are are known to concentrate mercury in their bodies. Consumption of these products gradually accumulate mercury in the body over time.

More specifically, fishes like swordfish, king mackerel and shark are known to concentrate higher amount of mercury than other species of fishes. Hence, limiting their consumption will protect humans from mercury poisoning.

The correct option is b.

irakobra [83]3 years ago
3 0

Answer:

B. Mercury.

Explanation:

Mercury enters the environment naturally and through industrial pollution, mostly from coal-fired power plants. Mercury concentrations in the air are of little concern, but when mercury enters water, microorganisms transform it to a highly toxic form methylmercury that builds up in fish.

These species of fish that are long-lived and high on the food chain, such as marlin, tuna, shark, swordfish and king mackerel contain higher concentrations of mercury than others.

Size is the best predictor of increased levels of accumulated mercury. This is because of its hierarchy on the food chain that is, once this mercury gets into the marine food chain, it accumulates in the larger predators. That’s why larger fish are generally riskier to eat than smaller ones.

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Fiesta28 [93]

Answer:

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3 years ago
Explain whether your breakfast was a compound, homogeneous mixture, or heterogenous mixture.
leonid [27]


what did you eat for breakfast?

I can't help you otherwise

7 0
3 years ago
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.</em>

<em />

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

<em>The moles of CH3COO- are its initial moles - the moles of HCl added</em>

<em>And moles of CH3COOH are its initial moles + moles HCl added</em>

<em />

Moles CH3COO-:

Initial moles  = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

<em>pH = 3.90</em>

<em />

<h3>The pH of the buffer is 3.90</h3>
3 0
3 years ago
Pls help with chemistry​
egoroff_w [7]

what are the questions?

5 0
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inna [77]

Answer: answer A

Explanation: because it gives more detail and a summarizations

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