1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergeinik [125]
2 years ago
5

Predict the Product

Chemistry
1 answer:
Taya2010 [7]2 years ago
8 0

Answer:

Answers with detail are given below.

Explanation:

C₆H₁₂O₆   →   2C₂H₅OH  + 2CO₂

Anaerobic respiration in plants produced ethanol which if accumulate then cause the harmful effect in plants. It is also occur in some microorganisms such as yeast.

C₆H₁₂O₆    →   2C₃H₆O₃

Anaerobic respiration in animals pyruvate converted into lactic acid and it is not as harmful as ethanol in plant if accumulate. It is produced during exercise. It can produce the cramps which can be cured with massage.

C₆H₁₂ + O₂       →       CO₂ + H₂O

This reaction is the combustion reaction of cyclohexane. Cyclohexane burnt in the presence of oxygen and form water and carbon dioxide.

You might be interested in
Help meeeeeeeeeeeeeee ​
lesya [120]

AMSWER :

CHEMICAL FORMULA :

• WATER - H2O

• CARBONDIOXIDE - CO2

• SODIUM HYDROXIDE - NaOH

• SULPHURIC ACID - H2SO4

• SODIUM CHLORIDE - NaCI

• SODIUM BICARBONATE - NaCHO3

8 0
2 years ago
Forensic chemistry
Rina8888 [55]

Explanation:

clinical laboratory test results are a very important parameter in diagnosis, monitoring and screening. 70-80 ... it is possible to determine whether you can interpret the test result as being ...

5 0
2 years ago
Used to measure temperature in 8th grade science.
zvonat [6]

Answer:

Fahrenheit

Explanation:

4 0
3 years ago
2. Calculate the atomic mass of an element that has two isotopes, each with 50.00% abundance. One isotope has a mass of 63.00 am
melamori03 [73]

Answer:

The atomic mass of element is 65.5 amu.

Explanation:

Given data:

Abundance of X-63 = 50.000%

Atomic mass of  X-63 = 63.00 amu

Atomic mass of X-68 = 68.00 amu

Atomic mass of element = ?

Solution:

Abundance of X-68 = 100-50 = 50%

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (50×63)+(50×68) /100

Average atomic mass =  3150 + 3400 / 100

Average atomic mass  = 6550 / 100

Average atomic mass = 65.5 amu.

The atomic mass of element is 65.5 amu.

7 0
3 years ago
When a gamma ray is emitted from the nucleus of an atom: it reduces the overall energy of the nucleus it increases the overall e
horrorfan [7]
When a gamma ray is emitted from the nucleus of an atom it reduces the overall energy of the nucleus. Emission of gamma rays almost happens along with beta and alpha emissions. After the two emissions, the nucleus of the atom would still be in an excited state. To achieve stability, gamma rays are emitted which will decrease the overall energy of the nucleus.
4 0
2 years ago
Other questions:
  • Explain why it is dangerous to burn a carbon-based fuel, such as propane or methane, in a closed room or building.
    9·1 answer
  • What type of solution is a soft drink
    9·1 answer
  • Identify the cfc with the shortest atmospheric lifetime
    10·1 answer
  • What is the most common acid and base?<br>and why?
    7·1 answer
  • Why is it necessary to mix the solution very rapidly when the bleach is added?
    12·1 answer
  • Which energy profile best shows that the enthalpy of formation of CS2 is 89.4 KJ/mol?
    8·2 answers
  • Question 1 (1 point)
    7·1 answer
  • How long does it take to fill one train car full of nuclear power can keep a power plant running
    8·1 answer
  • You have to make 500 mL of a 1.50 M BaCl2. You have 2.0 M barium chloride solution available. Determine how to make the needed d
    12·1 answer
  • The polypropylene (repeat unit CH₃CHCH₂) in a plastic toy has a molar mass of 2.8x10⁵ g/mol and a repeat unit length of 0.252 pm
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!