1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zubka84 [21]
3 years ago
12

According to Freud's theory, personality arises in response to conflicts between: a. our biological impulses and the social rest

raints against them. b. the collective unconscious and our individual desires. c. our unacceptable urges and our tendency to become self-actualized. d. the process of identification and the ego's defense mechanisms.
Biology
2 answers:
ira [324]3 years ago
4 0

Answer:

A

Explanation:

Elden [556K]3 years ago
4 0

Answer:A

Explanation:

Because due to the question you asked really think about option C. and D. they don't make much sense and naturally us humans do have a tendency to use a collective unconsciousness makes more sense and for our own desire also makes sense in a form or another, but I do believe B. Might be your best bet if that's not it then it must be choice A.

You might be interested in
The law of segregation predicts which phenomenon during gamete formation?.
Rudik [331]

A single random allele from each pair of parent alleles will be passed on to the gamete.

8 0
2 years ago
Three linked autosomal loci were studied in smurfs.
cupoosta [38]

Answer:

height -------- color --------- mood

           (13.2cM)      (14.5cM)

C=0.421

I = 0.579

Explanation:

We have the number of descendants of each phenotype product of the tri-hybrid cross.

Phenotype Number

  • pink, tall, happy            580
  • blue, dwarf, gloomy     601
  • pink, tall, gloomy         113
  • blue, dwarf, happy      107
  • blue, tall, happy              8
  • pink, dwarf, gloomy        6
  • blue, tall, gloomy          98
  • pink, dwarf, happy      101

Total number of individuals = 1614 = N

Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to know their order in the chromosome, and to do so, we need to compare the phenotypes of the parental with the ones of the double recombinants. We can recognize the parental in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent. So:

Parental)

  • Pink, tall, happy            580 individuals
  • Blue, dwarf, gloomy      601 individuals

Simple recombinant)

  • Pink Tall Gloomy           113 individuals
  • Blue, Dwarf, Happy       107 individuals
  • Blue Tall Gloomy             98 individuals
  • Pink Dwarf Happy          101 individuals

Double Recombinant)  

  • Blue Tall Happy                 8 individuals
  • Pink  Dwarf Gloomy           6 individuals  

Comparing them we realize that parental and double recombinant individuals differ in the position of the gene codifying for <u>color</u><u>.</u> They only change in the position of Blue and Pink. This suggests that the position of the color gene is in the middle of the other two genes, height and mood, because in a double recombinant only the central gene changes position in the chromatid.  

So, the alphabetic order of the genes is:

---- height ---- color ----- mood ----

Now we will call Region I to the area between Height and Color, and Region II to the area between Color and Mood.

Once established the order of the genes we can calculate distances between them, and we will do it from the central gene to the genes on each side. First We will calculate the recombination frequencies, and we will do it by region. We will call P1 to the recombination frequency between Height and color genes, and P2 to the recombination frequency between color and mood.

P1 = (R + DR) / N

P2 = (R + DR)/ N

Where: R is the number of recombinants in each region (the ones that have an intermediate phenotypic frequency), DR is the number of double recombinants in each region, and N is the total number of individuals.  So:

Region I

Tall------ Pink--------happy  (Parental) 580 individuals

Dwarf ---Pink------- Happy (Simple Recombinant) 101 individuals

Dwarf--- Pink-------Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Tall ------Blue------- Gloomy (Simple Recombinant)  98 individuals

Tall ----- Blue------- Happy   (Double Recombinant) 8 individuals  

Region II

Tall------ Pink--------happy (Parental) 580 individuals

Tall-------Pink------- Gloomy (Simple Recombinant) 113 individuals

Dwarf----Pink------- Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Dwarf ----Blue-------Happy (Simple Recombinant) 107 individuals

Tall ----- Blue------- Happy   (Double Recombinant) 8 individuals

In each region, the highlighted traits are the ones that suffered recombination.

  • P1 = (R + DR) / N

P1 = (101+6+98+8)/1614

P1 = 213/1614

P1 = 0.132    

  • P2= = (R + DR) / N

P2 = (113+6+107+8)/1614

P1 = 234/1614

P1 = 0.145

Now, to calculate the recombination frequency between the two extreme genes, height and mood, we can just perform addition or a sum:

  • P1 + P2= Pt

0.132 + 0.145 = Pt

0.277=Pt

The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).  

The map unit is the distance between the pair of genes for which every 100 meiotic products, one results in a recombinant product.  

Now we must multiply each recombination frequency by 100 to get the genetic distance in map units:

GD1= P1 x 100 = 0.132 x 100 = 13.2 MU = 13.2 cM

GD2= P2 x 100 = 0.145 x 100 = 14.5 MU = 14.5 cM

GD3=Pt x 100 = 0.277 x 100 = 27.7 MU = 27.7 cM

To calculate the coefficient of coincidence, CC, we must use the next formula:

CC= observed double recombinant frequency/expected double recombinant frequency

Note:  

-observed double recombinant frequency=total number of observed double recombinant individuals/total number of individuals

-expected double recombinant frequency: recombination frequency in region I x recombination frequency in region II.

  • CC= ((6 + 8)/1614)/0.132x0.145

        CC=0.008/0.019

        CC=0.421

The coefficient of interference, I, is complementary with CC.

I = 1 - CC

I = 1 - 0.421

I = 0.579

8 0
3 years ago
In guinea pigs, the color of the fur is determined by a single gene with two alleles control. The brown allele (B) is dominant o
Kipish [7]

Answer:

See

Explanation:

Given:

Brown allele (B) is dominant over the white allele (b).

It will be assumed that the alleles are not related to the X and Y chromosomes.

See attached diagram for details of the general case (for both homo-zygous and hetero-zygous parents)

For both parents hetero-zygous,

P1:

Genotype: Bb (100%)

Phenotype: brown (100%)

F1:

Genotypes : BB, Bb, bB and bb in equal proportions, i.e.

BB (25%), Bb (50%), bb (25%)

Phenotypes: 75% brown (from BB and Bb), 25% white (from bb)

8 0
3 years ago
Fault trees are an approach to hazard analysis that, for each identified hazard, break down that hazard to find how that hazard
Alexus [3.1K]

Hazards are placed at the root of the tree and determining the cause of the hazard is the correct option for the following hazard analysis questions.

Fault Tree Analysis (FTA) explores how selected “top” faults (abnormal conditions) or fault events such as accidental/unwanted releases of hazardous materials can be resolved to their causes. Hazard analysis is defined as the process of gathering and interpreting information about the hazards and conditions leading to their existence in order to determine what is food safety related and must be addressed in the HACCP plan. Hazard analysis is used as the first step in the risk assessment process. The result of hazard analysis is the identification of different types of hazards. A hazard is a potential condition that may or may not exist.

To know more about Hazard analysis visit:

brainly.com/question/10328303?referrer=searchResults

#SPJ4

4 0
10 months ago
Compared with a eukaryotic cell, a prokaryotic cell Select one:______
juin [17]

Answer:

The correct option is a. lacks organelles beyond ribosomes.

Explanation:

All cells of higher organisms are bounded by a cell membrane (also called plasma membrane or plasmalema) and contain cytoplasm that surrounds one or more nuclei. Within the cytoplasm there are structures known as organelles, which are specialized in carrying out the metabolic processes of the cell, these cells are called eukaryotes. The prokaryotes are smaller, lack a differentiated nucleus and organelles. The prokaryotic cells are not internally divided by membranous walls, but consist of a single space.

Both prokaryotic and eukaryotic cells contain ribosomes. Ribosomes are organelles not delimited by membranes, these organelles are important since a cell makes all its proteins in its ribosomes.

8 0
3 years ago
Other questions:
  • The Clean Water Act does not ensure high water quality throughout the nation because it does not _____.
    14·2 answers
  • What is the diligent search for an answer or a solution to a problem called?
    7·1 answer
  • Cellular respiration, as well as other body processes, produces wastes. These wastes must be eliminated from the body in order f
    14·1 answer
  • Which two terms indicate the same area of the body?
    13·2 answers
  • A neuron receives a number of EPSPs from many different neurons. If a sufficient number of EPSPs are received, the neuron respon
    7·1 answer
  • Which of the following is an example of a point source of population?
    15·1 answer
  • You want points to deez
    11·2 answers
  • In order to perceive forms and patterns from incoming stimuli, individuals utilize____.
    7·2 answers
  • Helpppppp me please
    15·1 answer
  • Explain how the nitrogen cycle works
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!