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BARSIC [14]
3 years ago
6

How to get answer in ratio fraction in simplest form ? 6 poodles out of 18 dogs

Mathematics
2 answers:
shtirl [24]3 years ago
5 0
6/18 is the same as 1/3
Virty [35]3 years ago
5 0
 6                 1
---      =      ---
18               3

because 6 is 1/3 of 18
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If your answer is b<img src="https://tex.z-dn.net/?f=%5Cneq" id="TexFormula1" title="\neq" alt="\neq" align="absmiddle" class="l
adelina 88 [10]

Answer:

This means that b is not equal to -10.

3 0
2 years ago
2895÷229=<br> PLZ RIGHT WITH WHOLE NUMBER AND REMANDER<br> ---<br> R:
Eduardwww [97]

Answer:

12 R 147

Step-by-step explanation:

6 0
2 years ago
Without using technology, describe the end behavior of f(x) = 3x32 + 8x2 − 22x + 43. (2 points)​
Elis [28]

Answer:

This function is an even-degree polynomial, so the ends go off in the same directions, just like every quadratic I've ever graphed. Since the leading coefficient of this even-degree polynomial is positive, the ends came in and left out the top of the picture, just like every positive quadratic you've ever graphed. All even-degree polynomials behave, on their ends, like quadratics.

Step-by-step explanation:

3 0
3 years ago
Ok so this is so confusing The volume of water in a rectangular swimming pool can be modeled by the polynomial 2x3 _ 9x2 + 7x +
Alika [10]
The volume formula is V= l x L x H, l=width, L=Length, H= Depth, so 
2x3 _ 9x2 + 7x + 6 = l x L x (2x + 1), because H=(2x + 1), so 
l x L= (2x3 _ 9x2 + 7x + 6 )/ (2x + 1) = (2x3 _ 9x2 + 7x + 6 ) X [1/(2x + 1)]
case1: l= (2x3 _ 9x2 + 7x + 6 ) or L= 1/(2x + 1), case2: L= (2x3 _ 9x2 + 7x + 6 ) or l= 1/(2x + 1)
the why question:
perhaps there is similarity of value between volume and l, or volume and L
6 0
3 years ago
Compute each sum below. If applicable, write your answer as a fraction.
Alex777 [14]

Answer:

First equation is -425

Second equation is 11.25

Step-by-step explanation:

First equation we can write as

\sum_{i=0}^7 5 \times (-2)^i

computing

When i=0 -> 5 \times (-2)^0 =5

When i=1 -> 5 \times (-2)^1 = -10

...

When i=7 -> 5 \times (-2)^7 = --640

then replacing each term we have

5  + (-10) + ( 20) + ( -40) +  (80) +( -160) +   320 + (-640) = -425

For the second equation we'll have 9 terms, solving in a similar fashion

When i=1 -> \frac{1}{4}1=0.25

When i=2 -> \frac{1}{4}2=0.50

When i=3 -> \frac{1}{4}3=0.75

...

When i=9 -> \frac{1}{4}9=2.25

So we have 0.25 + 0.50 + 0.75 + 1.00 + 1.25 + 1.50+ 1.75 +2.00 +2.25

4 0
3 years ago
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