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3 years ago

Which function is the inverse of f(x) = 2x + 3?

Mathematics

2 answers:

Ierofanga [76]3 years ago

5 0

(x-3)/2 i believe, good luck

Veseljchak [2.6K]3 years ago

3 0

F(x)= 2x + 3 then y = 2x + 3 then x = 2y + 3 then x - 3 = 2y

ANSWER : -1 x - 3
f (x) = _____

2

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Can someone help, me

Radda [10]

The answer to #5 is 33.

8 0

3 years ago

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Solve for b in: (2B/x)-Q=Z

andrezito [222]

Answer:

B = (zx/2)+ (qx/2)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

(-8, -1) slope = -3/4

babunello [35]

Answer:

y=-3/4x - 7

Step-by-step explanation:

When finding the slope given a point and a slope, we do the following.

y=mx+b (Slope-intercept Form)

m is the slope and x,y are the points

Plug in everything

-1= -3/4(-8)+b

Multiply

-1 = 6 + b

-7 = b

This gives us the final equation of y=-3/4x - 7

7 0

3 years ago

2^2/5+ 3^1/10 <br> HELP ASAP

gizmo_the_mogwai [7]

Answer:

$\sqrt[5]{4}$ + $\sqrt[10]{3}$

Step-by-step explanation:

We sure can write 2^2/5+ 3^1/10 as $2^{\frac{2}{5} } + 3^{\frac{1}{10} }$

// use the $a^{\frac{m}{n} } =\sqrt[n]{a^{m} }$ to transform the expression

Convert $2^{\frac{2}{5} }$ to $\sqrt[5]{2^{2} }$ = $\sqrt[5]{4}$ (here a = 2, n = 5, m = 2)

Then convert $3^{\frac{1}{10} }$ to $\sqrt[10]{3^{1} }$ = $\sqrt[10]{3}$ (here a = 3, n = 10, m = 1)

Now we get $2^{\frac{2}{5} } + 3^{\frac{1}{10} }$ = $\sqrt[5]{4}$ + $\sqrt[10]{3}$ . This is the simplified form, which is the answer.

6 0

3 years ago

1. if a = 16 and b= 12, find c

klasskru [66]

Answer:

Step-by-step explanation:

The pythagorean theorem states that

$a^2+b^2=c^2$

So $16^2 + 12^2 = c^2\\256+144 = c^2\\400 = c^2$

You would then do

$400 = c^2\\\sqrt{400} = c$

Because a square root is the opposite of a square.

$\sqrt{400} = 20$

because 20 * 20 = 400

7 0

3 years ago