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pogonyaev
3 years ago
6

write the formula of the parabola that has x-intercepts (1.3,0) and (-1.3,0), and y-intercept (0,169)

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

y= 169 −  100^{2}

Step-by-step explanation:

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Verifying Trig Functions
anzhelika [568]

Answer:

The answer to your question is below

Step-by-step explanation:

                csc α - cot α = \frac{sin \alpha }{1 + cos \alpha }

Work with the left part

                \frac{1}{sin\alpha } - \frac{cos \alpha }{sin \alpha}

Simplify

                \frac{1 - cos\alpha }{sin\alpha }

Multiply by the reciprocal

 \frac{1 - cos\alpha }{sin \alpha } x \frac{1 + cos\alpha }{1 + cos\alpha }                                  

Simplify

\frac{1 - cos^{2}\alpha}{sin\alpha (1 + cos\alpha)}

Remember that

                 sin²α = 1 -cos²α

Substitute the previous equation

\frac{sin^{2}\alpha }{sin\alpha(1 + cos\alpha ) }

Simplify

\frac{sin\alpha}{1 + cos \alpha}      

The identity i proved.            

5 0
3 years ago
Emmanuel carves a cone-shaped hollow out of a solid clay cylinder. What is the approximate volume of the solid portion of the cy
bixtya [17]

Answer:

3.14r^2(h-\frac{1}{3}h_1)

Step-by-step explanation:

Let h be the cylinders height and r the radius.

-The volume of a cylinder is calculated as:

V=\pi r^2h

-Since the cone is within the cylinder, it has the same radius as the cylinder.

-Let h_1be the height of the cone.

-The area of a cone is calculated as;

V=\pi r^2 \frac{h}{3}\\\\=\frac{1}{3}\pi r^2h_1

The volume of the  solid section of the cylinder is calculated by subtracting the cone's volume from the cylinders:

V=V_{cy}-V_{co}\\\\=\pi r^2h-\frac{1}{3}\pi r^2 h_1, \pi=3.14\\\\=3.14r^2(h-\frac{1}{3}h_1)

Hence, the approximate area of the solid portion is 3.14r^2(h-\frac{1}{3}h_1)

5 0
3 years ago
 The difference between the product of four and a number and six
Olin [163]
Answer- 4x-6
explain- i got it right
5 0
3 years ago
PLEASE HELPP MEE ASAPP!!
WARRIOR [948]

Answer:

Step-by-step explanation:

each zero of the function will have a factor of (x - x₀)

h(x) = a(x + 3)(x + 2)(x - 1)

h(x) = a(x + 3)(x² + x - 2)

h(x) = a(x³ + 4x² + x - 6)

or the third option works if a = 1

however this equation gives us the points (0, -6) and (-1. -4), so "a" must be -2

h(x) = -2x³ - 8x² - 2x + 12

to fit ALL of the given points as it fits the three zeros and also h(0) and h(-1) so I guess that is why the given group is a <u><em>partial</em></u> set of solution sets

7 0
3 years ago
A researcher read a 12-page article in 30 minutes. On
neonofarm [45]
Answer: 2.5 minutes

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3 0
4 years ago
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