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vichka [17]
3 years ago
9

Please both the question please ​

Mathematics
2 answers:
PtichkaEL [24]3 years ago
7 0

Answer:

Boys: 2/17

Girls: 4/17

Step-by-step explanation:

2 + 15 = 17 (to get the total number of boys in Sapphire's class)

4 + 13 = 17 (to get the total number of girls in the class)

The proportion is how many who are left handed over the total number of girls/boys. ^^

So, left-handed for boys = 2, which makes the proportion 2/17

And there are 4 left-handed girls, so the proportion is 4/17

Alexus [3.1K]3 years ago
3 0
Answer: (i) 2/6=0.33 and (ii) 4/6=0.66
Explanation: if you were to add everything up there would be 17 boys and 17 girl and then you would end up with 6 people who write with their left hand and 28 people who right with their right hand. I hope this helps
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a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer.
miss Akunina [59]

Answer:

\frac{1}{990}

Step-by-step explanation:

<u>The full question:</u>

<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current​ positions?"</em>

<em />

<em />

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = \frac{n!}{(n-r)!}

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = \frac{11!}{(11-3)!}=\frac{11!}{8!}=11*10*9=990

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990

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3 years ago
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