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vichka [17]
3 years ago
9

Please both the question please ​

Mathematics
2 answers:
PtichkaEL [24]3 years ago
7 0

Answer:

Boys: 2/17

Girls: 4/17

Step-by-step explanation:

2 + 15 = 17 (to get the total number of boys in Sapphire's class)

4 + 13 = 17 (to get the total number of girls in the class)

The proportion is how many who are left handed over the total number of girls/boys. ^^

So, left-handed for boys = 2, which makes the proportion 2/17

And there are 4 left-handed girls, so the proportion is 4/17

Alexus [3.1K]3 years ago
3 0
Answer: (i) 2/6=0.33 and (ii) 4/6=0.66
Explanation: if you were to add everything up there would be 17 boys and 17 girl and then you would end up with 6 people who write with their left hand and 28 people who right with their right hand. I hope this helps
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Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
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<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
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