Question

A jet aircraft with a mass of 4,475 kg has an engine that exerts a force (thrust) equal to 60,800 N. (a) What is the jet's acceleration? (Give the magnitude.) (b)What is the jet's speed after it accelerates for 5 s? (Assume it starts from rest.) (c) How far does the jet travel during the 5 s?

Answer 1

Answer:

a) 13.59 m/s²

b) 67.95 m/s

c) 169.875 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass

Force

$F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{60800}{4475}\\\Rightarrow a=13.59\ m/s^2$

Acceleration of the jet is 13.59 m/s²

$v=u+at\\\Rightarrow v=0+13.59\times 5\\\Rightarrow v=67.95\ m/s$

Velocity attained at 5 seconds is 67.95 m/s

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{67.95^2-0^2}{2\times 13.59}\\\Rightarrow s=169.875\ m$

Distance traveled in the 5 seconds is 169.875 m

Answer 2

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Explanation: