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3 years ago

6

The earth is rotating on its axis. It will continue to rotate unless acted upon by an outside force. This is an example of Newto

n's _____.
first law of motion
second law of motion
third law of motion

2 answers:

mojhsa [17]3 years ago

7 0

It is an example of Newton’s first law.

agasfer [191]3 years ago

5 0

Answer:

I think it's an example of his first law of motion

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A machine shop worker reports the mass of an aluminum cube as 176 g. If one side of the cube measures 4 cm, what is the density

Zarrin [17]

-- Since it's a cube, its length, width, and height are all the same 4 cm .

-- Its volume is (length x width x height) = 64 cm³ .

-- Density = (mass) / (volume)

= (176 g) / (64 cm³)

= 2.75 gm/cm³ .

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A simple machine does work because it applies

tigry1 [53]

Force
or motion im not toatally sure

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3 years ago

To measure the internal diameter of a beaker one would reliably use______.

erik [133]

Answer:

Vernier calipers is used to measure the internal diameter of a beaker

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3 years ago

A hockey puck is hit on a frozen lake and starts moving with a speed of 12.0 m/s. exactly 5.0 s later, its speed is 6.0 m/s. wha

Anna35 [415]

1) In an uniformly accelerated motion, the acceleration is given by:
$a= \frac{v_f-v_i}{\Delta t}$
where $v_f$ is the final speed, $v_i$ is the initial speed, and $\Delta t$ is the time interval between the initial and final point of the motion.

Using the data of the problem: $v_i = 12.0 m/s$ , $v_f = 6.0 m/s$ , and the time $\Delta t = 5.0 s$ , the acceleration is
$a= \frac{6 m/s-12 m/s}{5.0 s}=-1.2 m/s^2$
where the negative sign means that the hockey puck is decelerating.

2) The frictional force F between the puck and ice is responsible for the deceleration of the puck, and for second Newton's law this force is equal to the product between the mass of the puck m and the acceleration:
$F=ma$ (1)
The frictional force can also be written as
$F=-\mu_D mg$ (2)
where $\mu_D$ is the coefficient of kinetic friction, and where the negative sign is due to the fact that the frictional force acts against the direction of motion of the puck. By equilizing (1) and (2) we can find the value of this coefficient:
$ma=-\mu_D mg$
$\mu_D = -\frac{a}{g}= -\frac{-1.2 m/s^2}{9.81 m/s^2}=0.12$

5 0

4 years ago

A cubical Gaussian surface surrounds two positive charges, each has a charge q 1 1 = + 3.90 × 10 − 12 3.90×10−12 C, and three ne

Masteriza [31]

Answer:

The electric flux is zero because charge is zero.

Explanation:

Given that,

Positive charge $q_{1}=3.90\times10^{-12}\ C$

Negative charge $q_{2}=-2.60\times10^{-12}\ C$

We need to calculate the total charged

Using formula of charge

$Q_{enc}=2q_{1}+3q_{2}$

Put the value into the formula

$Q_{enc}=2\times3.90\times10^{-12}+3\times(-2.60\times10^{-12})$

$Q_{enc}=0$

We need to calculate the electric flux

Using formula of electric flux

$\phi=\dfrac{Q_{enc}}{\epsilon_{0}}$

Put the value into the formula

$\phi=\dfrac{0}{8.85\times10^{-12}}$

Hence, The electric flux is zero because charge is zero.

7 0

3 years ago