The earth is rotating on its axis. It will continue to rotate unless acted upon by an outside force. This is an example of Newto
2 answers:
You might be interested in
Answer:
9 meters
Explanation:
Given:
Mass of Avi is,
Spring constant is,
Compression in the spring is,
Let the maximum height reached be 'h' m.
Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.
So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.
Decrease in elastic potential energy is given as:
Now, increase in gravitational potential energy is given as:
Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,
Therefore, Avi will reach a maximum height of 9 meters.
Answer:
14,300 lines per cm
Explanation:
Answer:
14,300 cm per line
Explanation:
λ400 nm to 400nm
We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.
mλ = dsin (θ)
In this equation,
m is the order of diffraction.
λ is the wavelength of the incident light.
d is the distance separating the centers of the two slits.
θ is the angle at which the mth order would diffract.
To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.
d = mλ / sin (θ)
As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.
d = mλ / sin (θ)
d = 1 x 700nm / 1
= 700 nm
So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.
n = 1/d
= 1 / 700 x
= 1, 430,000 lines per m
= 14,300 lines per cm
<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>