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3 years ago

6

The earth is rotating on its axis. It will continue to rotate unless acted upon by an outside force. This is an example of Newto

n's _____.
first law of motion
second law of motion
third law of motion

2 answers:

mojhsa [17]3 years ago

7 0

It is an example of Newton’s first law.

agasfer [191]3 years ago

5 0

Answer:

I think it's an example of his first law of motion

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A centrifuge accelerates uniformly from rest to 15000 rpm in 330 s . Through how many revolutions did it turn in this time?

eduard

Answer:

The number of revolutions turned by the centrifuge is 8250 revolutions.

Explanation:

Given;

number of revolution per minutes, ω = 15000 rpm

time of motion, t = 330 s = 5.5 minutes

The number of revolutions turned by the centrifuge is given by;

$N = \frac{1500 \ Rev}{minutes} *5.5 \ minutes\\\\N = 8250 \ revolutions$

Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.

4 0

3 years ago

A baseball is hit almost straight up into the air with a speed of 26 m/s . Estimate how high it goes.

kipiarov [429]

Answer:

The maximum height of the ball is 34.5 m.

The ball is 5.31 s in the air.

Explanation:

Hi there!

The equations for the height and velocity of the baseball that is hit straight up are as follows:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the baseball at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

v = velocity at time t.

If we place the origin of the frame of reference at the place where the baseball is hit, then, y0 = 0.

To calculate how high it goes, we have to obtain the time at which the ball is at maximum height. At that point, the velocity is 0. Then using the equation of velocity:

v = v0 + g · t

0 = 26 m/s - 9.8 m/s² · t

-26 m/s / -9.8 m/s² = t

t = 2.65 s

The height at that time will be the maximum height:

y = y0 + v0 · t + 1/2 · g · t² (y0 = 0)

y = 26 m/s · 2.65 s - 1/2 · 9.8 m/s² · (2.65 s)²

y = 34.5 m

The maximum height of the ball is 34.5 m

If it takes the ball 2.65 s to reach the maximum height it will take another 2.65 s to return to the initial position. Then, the time it will be in the air is (2.65 s + 2.65 s) 5.30 s. However, let´s calculate the time it takes the ball to reach the initial position using the equation for height.

At the initial position y = 0. Then:

y = y0 + v0 · t + 1/2 · g · t² (y0 = 0)

0 = 26 m/s · t - 1/2 · 9.8 m/s² · t²

0 = t (26 m/s - 1/2 · 9.8 m/s² · t) (t = 0 when the ball is hit)

0 = 26 m/s - 1/2 · 9.8 m/s² · t

-26 / -4.9 m/s² = t

t = 5.31 s ( the difference with the 5.30 s obtained above is due to rounding the time to 2.65 s).

The ball is 5.31 s in the air.

Have a nice day!

3 0

3 years ago

A person carries a mass of 10 kg and walks along the +x-axis for a distance of 100m with a constant velocity of 2 m/s. What is t

gizmo_the_mogwai [7]

Since the direction of the force and the direction of the path is perpendicular, the person is not doing any physical work.

3 0

3 years ago

Read 2 more answers

A skydiver has a mass of 140 kg. At what speed will she have a momentum<br> of 10,000 kg•m/s?

liq [111]

Answer:

I think its 71.4 if u get it wrong u can slap me

8 0

3 years ago

a plane gate of uniform thickness holds back a depth of water Show that the vertical component of the hydrostatic force F acting

Alenkasestr [34]

Answer:

The question is incomplete with some details missing, but here is the complete question ; A plane gate of uniform thickness holds back a depth of water as shown in the figure. The gate thickness is 2 m, the length L is equal to 3 m, and the angle 0 equals 30°. Determine a. The average pressure on the gate . b. The hydrostatic force F applied to the gate and its components, vertical and horizontal .

Explanation:

The detailed calculation using the relationship between pressure and force applied is as shown in the attachment.

3 0

4 years ago