The magnetic moment is -
M = 5.5 x 
A
.
We have current carrying single circular loop placed in a magnetic field
parallel to the plane of the loop.
We have to determine the Magnetic moment of the loop.
<h3>What is the formula to calculate the magnetic moment of loop?</h3>
The formula to calculate the magnetic moment of the loop is -
M = NIA
where -
N - Number of turns
I - Current in the loop
A - Area of the loop
According to the question, we have -
I = 17mA = 0.017A
Circumference (C) = 2 meters
B = 0.8 T
Now -
C = 2
2
r = 2
r = 1
r = 
r = 0.32
Using the formula -
M = NIA
M = NI
M = 3.14 x 1 x 0.017 x 0.32 x 0.32
M = 3.14 x 4 x 0.017
M = 5.5 x A
Hence, the magnetic moment is -
M = 5.5 x A
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Answer:
See below
Explanation:
Vertical position = 45 + 20 sin (30) t - 4.9 t^2
when it hits ground this = 0
0 = -4.9t^2 + 20 sin (30 ) t + 45
0 = -4.9t^2 + 10 t +45 = 0 solve for t =4.22 sec
max height is at t= - b/2a = 10/9.8 =1.02
use this value of 't' in the equation to calculate max height = 50.1 m
it has 4.22 - 1.02 to free fall = 3.2 seconds free fall
v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL
it will <u>also</u> still have horizontal velocity = 20 cos 30 = 17.32 m/s
total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s
Horizontal range = 20 cos 30 * t = 20 * cos 30 * 4.22 = 73.1 m
Answer:
Explanation:
A fuse is an electrical safety device built around a conductive strip that is designed to melt and separate in the event of excessive current. Fuses are always connected in series with the component(s) to be protected from overcurrent, so that when the fuse blows (opens) it will open the entire circuit and stop current through the component(s). A fuse connected in one branch of a parallel circuit, of course, would not affect current through any of the other branches.
1) Ecology
2) Food Web
3) Trophic Level
4) Producer
5) Autotroph
6) Consumer
7) Heterotroph
8) Decomposer
Hope tHis Helps ._.
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