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Nikolay [14]
3 years ago
11

A 10.0-kg box starts at rest on a level floor. An external, horizontal force of 2.00 × 102 N is applied to the box for a distanc

e of 4.00 m. If the coefficient of kinetic friction between the box and the floor is 0.440, how fast is the block moving at the end of the 4.00 m? Assume it starts from rest.
Physics
1 answer:
Harman [31]3 years ago
7 0

Answer:

vf = 11.2 m/s

Explanation:

m = 10 Kg

F = 2*10² N

x = 4.00 m

μ = 0.44

vi = 0 m/s

vf = ?

We can apply Newton's 2nd Law

∑ Fx = m*a   (→)

F - Ffriction = m*a  ⇒  F - (μ*N) = F - (μ*m*g) = m*a   ⇒  a = (F - μ*m*g)/m

⇒    a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²

then , we use the equation

vf² = vi² + 2*a*x    ⇒    vf = √(vi² + 2*a*x)

⇒   vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s

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Dante is leading a parade across the main street in front of city hall. Starting at city hall, he marches the parade 4 blocks ea
Yuliya22 [10]

Answer:

The displacement is 6.71 [m} and the angle is 63.4° to the north of east

Explanation:

Using a sketch showing Dante's displacement, we can find each of the points Dante moves through. First, it moves 4 blocks east, the new coordinate (4.0), then moves 3 blocks south and we will get the new coordinate (4, -3). Then Dante moves 1 block west, thus the new point is (3, -3). And finally it moves 9 blocks north where the new coordinate in and gets -3 - (-9) = + 6.

The displacement can be found using the equation for the straight line.

d= \sqrt{(x_{1}-x_{0} )^{2} +(y_{1}-y_{0} )^{2} } \\d= \sqrt{(3-0 )^{2} +(6-0 )^{2} } \\\\d=6.71 [m]\\

We can realize that the triangle formed is a right triangle, therefore we can find the angle of the displacement.

tan(a)=\frac{6}{3} \\a=tan^-1(2)\\a=63.4[deg]

8 0
3 years ago
How long was a 50 W lightbulb left on for if 500,002 J were burned?
saveliy_v [14]

" 50 W " means " 50 Watts "  or  " 50 Joules per second ".

(500,002 J) / (50 J/sec)  =  <em>10,000.04 seconds</em>

(That's 2 hours 46 minutes 40.04 seconds.)

3 0
3 years ago
Find the length of each vector below.
Leona [35]

Answer:

a. 3.6 units

b. 1.4 units

c. 3.6 units

d. 6.1 units

Explanation:

The length of a vector is given by the following formula:

Length = √(x² + y²)

where,

x = x-component of vector

y = y-component of vector

a.

Here,

x = 2

y = 3

Therefore,

Length = √(2² + 3²)

Length = √13

<u>Length = 3.6 units</u>

<u />

b.

Here,

x = 1

y = 1

Therefore,

Length = √(1² + 1²)

Length = √2

<u>Length = 1.4 units</u>

<u />

c.

Here,

x = 2

y = -3

Therefore,

Length = √(2² + (-3)²)

Length = √13

<u>Length = 3.6 units</u>

<u />

d.

Here,

x = 1

y = -6

Therefore,

Length = √(1² + (-6)²)

Length = √37

<u>Length = 6.1 units</u>

8 0
3 years ago
Why is copper a pure substance? A. Because it is an element B. Because it is a compound C. Because it is a homogenous mixture​
expeople1 [14]
A) because it is an element.
Explanation: usually when they say pure substance they mean pure element.
Hope this helped!! :)
3 0
3 years ago
A person of Mass 50kg is on a swing which has the speed 10m,/s at the lowest point of the motion the ropes of the swing are 2.5m
atroni [7]

Answer:

T  =  2490 newton

Explanation:

Given that,

Mass of a person, m = 50 Kg

Speed of the swing at the lowest point, v = 10 m/s

Length of the rope, r = 2.5 m

Tension formula is given by

                            T = mg + ma  N

where,              T - Tension in the string

                         m - mass of the body

                         g - acceleration due to gravity

                          a - acceleration of the body

Since the person is swinging, the acceleration of the body is given by

                          a = v²/r m/s²

                             = 10/2.5  m/s²

                          a = 40 m/s²

Substituting in T

                   T  =  50 Kg x 9.8 m/s²  + 50 Kg X 40 m/s²

                       = 490 + 2000 Kg m/s²

                   T  =  2490 newton

Therefore the tension in the rope is 2490 newton

8 0
4 years ago
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