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Tems11 [23]
3 years ago
12

If a ball is dropped into a very viscous liquid it will

Physics
1 answer:
Dafna1 [17]3 years ago
7 0
It will go to the bottom of the liquid very slowly. Good Luck!
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The initial and final velocities of two blocks experiencing constant acceleration are respectively −7.45 m/s and 14.9 m/s. (a) T
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Answer:

a) a_{1}=3.7 m/s^{2}

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Explanation:

a) The displacement of the first object is 22.5 m, so we can use the next equation:

v_{f}^{2}=v_{i}^{2}+2a\Delta x

a=\frac{v_{f}^{2}-v_{i}^{2}}{2x}

a=\frac{14.9^{2}-(-7.45)^{2}}{2*22.5}

a_{1}=3.7 m/s^{2}

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b) Using the same equation we can find the second value of the acceleration:

a=\frac{v_{f}^{2}-v_{i}^{2}}{2x}

a=\frac{14.9^{2}-(-7.45)^{2}}{2*22.6}

a_{2}=3.68 m/s^{2}

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