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Anna11 [10]
4 years ago
10

Help me asap Please!!!

Mathematics
1 answer:
BabaBlast [244]4 years ago
7 0
3.14, 2.2, 2.85, 4.4

In order they would be

Sqrt(5), Sqrt(8), pi, 2Sqrt(5)
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In the fifth year of operation the profit of a company was 3 times the profit it earned in the first year of operation if its pr
bogdanovich [222]
Let the profit at the first year be X
3x=114000
Solve for x by dividing each side by 3

3x/3=114000/3
X=38,000

So the profit was 38000
4 0
3 years ago
During a sale, fidget spinners 1/4 off the regular price. If a spinner regularly costs 5.90, what is the sale price
garik1379 [7]

price - (1/4)×price = price×(1 - 1/4) = (3/4)×price

... = (3/4)×5.90 = 4.425 ≈ 4.43 . . . . . sale price

_____

The sale price could be 4.42 if the discount is rounded up, rather than the price being rounded up. If you first compute the discount as (1/4)×5.90 = 1.475 ≈ 1.48, then the half-penny goes to the customer, not the shop-keeper.

8 0
3 years ago
Find the mistake in this problem: 3(x+2)= 3x+2
Harrizon [31]
A)should of multiplied the 3 with the 2
6 0
3 years ago
A guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.
frutty [35]

Answer:

The length of the wire is 76.19 m.

Step-by-step explanation:

It is given that a guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

It means base of the right angled triangle is 40 m.

The wire makes an angle of 58deg 20min with the ground.

1 degree = 60 min

Using this conversion convert the given angle in degree.

58^{\circ}20'=58^{\circ}\frac{20}{60}^{\circ}=58\frac{1}{3}^{\circ}=\frac{175}{3}^{\circ}

In a right angled triangle

\cos \theta=\frac{adjacent}{hypotenuse}

\cos (\frac{175}{3}^{\circ})=\frac{40}{hypotenuse}

0.525=\frac{40}{hypotenuse}

hypotenuse=\frac{40}{0.525}

hypotenuse=76.190

Therefore the length of the wire is 76.19 m.

3 0
3 years ago
What is the answer to this: -5a+3>1
Andreas93 [3]

The answer to this problem is

a <  \frac{2}{5}

7 0
3 years ago
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