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Oksi-84 [34.3K]
3 years ago
9

6,651,297,000 in verbal form

Mathematics
1 answer:
sashaice [31]3 years ago
7 0
Six billion, six hundred fifty one million, two hundred ninety seven thousand. 
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Find a point on the y-axis that is equidistant from the points (8, −8) and (1, 1).
artcher [175]

\text{We know that any point on the y-axis is of the form (0, y),}\\&#10;\text{because on y-axis we have x=0.}\\&#10;\\&#10;\text{So let (0, y) be the point on the y-axis that is equidistance from}\\&#10;\text{the points }(8,-8) \text{ and }(1,1)\\&#10;\\&#10;\text{so using the distance formula, we have}\\&#10;\\&#10;\text{Distance between (0, y) and }(8,-8)=\text{Distance between (0,y) and }(1,1)\\&#10;\\&#10;\Rightarrow \sqrt{(0-8)^2+(y-(-8))^2}=\sqrt{(0-1)^2+(y-1)^2}

\Rightarrow \sqrt{64+(y+8)^2}=\sqrt{1+(y-1)^2}\\&#10;\\&#10;\text{Squaring both sides, we get}\\&#10;\\&#10;(\sqrt{64+(y+8)^2})^2=(\sqrt{1+(y-1)^2})^2\\&#10;\\&#10;\Rightarrow 64+(y+8)^2=1+(y-1)^2\\&#10;\\&#10;\Rightarrow 64+(y^2+16y+64)=1+(y^2-2y+1)\\&#10;\\&#10;\Rightarrow y^2+16y+128=y^2-2y+2\\&#10;\\&#10;\Rightarrow y^2+16y-y^2+2y=2-128\\&#10;\\&#10;\Rightarrow 18y=-126\\&#10;\\&#10;\Rightarrow y=\frac{-126}{18}\\&#10;\\&#10;\Rightarrow y=-7

So the point on the y-axis that is equidistant from the points (8,-8) and (1,1) is: (0,-7)

3 0
4 years ago
The coefficient of a² in 5 a² + 8 ab is (im asking something normal this time lol)
julsineya [31]

Answer:

5

Step-by-step explanation:

coefficient is a number before a letter in this case itz 5

4 0
3 years ago
A certain kind of spider is about 8 millimeters wide. How many of these spiders would fit side by side on a meter stick?
Vladimir79 [104]
Because there are 1000 millimeters in one meter, we can divide 1000 by 8 to see that 125 spiders that are 8mm long would fit side by side on a meter stick.
7 0
4 years ago
If a dinner cost $125 and you leave a $21.25 for a tip what percent do you tip ?
natka813 [3]
21.25/ 125 = 0.17
17 % tip
6 0
3 years ago
An airplane climbs at an angle of 2.7" from an altitude of 4500 ft to an altitude of 5600 ft. How far does the airplane travel a
Dvinal [7]

Answer:

  23,325 ft, about 4.42 miles

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle, where the side adjacent to the 2.7° angle of climb is the horizontal distance, and the side opposite is the vertical change in altitude. That change is ...

  5600 ft -4500 ft = 1100 ft

and the angle relation is ...

  tan(2.7°) = opposite/adjacent = (1100 ft)/(horizontal distance)

Multiplying this equation by (horizontal distance)/tan(2.7°) gives ...

   horizontal distance = (1100 ft)/tan(2.7°) ≈ 23,325 ft

Dividing this by 5280 ft/mi gives ...

  horizontal distance ≈ 4.42 mi

The airplane travels about 23,325 ft, or 4.42 miles, horizontally as it climbs.

4 0
3 years ago
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