Daniel has a beginning balance of $675 in his checking account. He writes two checks for $530 and $200. He has a deposit of $340
1 answer:
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Answer:
- Only Drawing D has KL being a symmetrical segment.
- Drawings A, B and C have no axis of symmetry.
- Tylko rysunek D ma KL będący segmentem symetrycznym.
- Rysunki A, B i C nie mają osi symetrii.
Step-by-step explanation:
English Translation
In which drawing was the symmetrical segment of KL drawn? Which of these letters has no axis of symmetry?
Solution
The attached image to the question is presented in the attached image to this Solution.
Symmetry is a concept where a figure/shape has half of its part being a mirror image of the other part.
About the line or axis of symmetry, the structure or figure can be rotated at right angles or whole number multiples of right angles and the resulting structure is still the same as the one we started with.
Of the 4 drawings, only drawing D satisfies this conditions/criteria. And Hence, it is the only drawing amongst the four with an axis of symmetry.
In Polish/Po polsku
Załączony obraz do pytania jest przedstawiony na załączonym obrazku do tego rozwiązania.
Symetria to koncepcja, w której figura / kształt ma połowę swojej części stanowiącą odbicie lustrzane drugiej części.
W odniesieniu do linii lub osi symetrii, strukturę lub figurę można obracać pod kątem prostym lub wielokrotności liczby całkowitej pod kątem prostym, a wynikowa struktura jest nadal taka sama jak ta, od której zaczęliśmy.
Z 4 rysunków tylko rysunek D spełnia te warunki / kryteria. I dlatego jest to jedyny rysunek wśród czterech z osią symetrii.
Hope this Helps!!!
Mam nadzieję że to pomoże!!!
Answer:
Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:
where:
a=0
so the volume becomes:
This can be simplified to:
and the integral can be rewritten like this:
which is a standard integral so we solve it to:
so we get:
which yields:
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