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3 years ago

Which property of real numbers is shown below? -6 + 6 = 0

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

Answer:

Additive inverse property

Step-by-step explanation:

When you add opposites you get 0.

Another word for opposites is additive inverses.

This is the additive inverse property.

It says when you do -a+a or a+(-a) you get 0 for any number a.

Airida [17]3 years ago

3 0

Answer:

Additive inverse property.

Step-by-step explanation:

We are given that an expression

$-6+6=0$

We have to find which property of real numbers is shown in the given expression.

Additive inverse property of real number :It is that property by which when a number is added to its negative value of the number then sum will be zero.

Mathematical representation

$a+(-a)=-a+a=0$

Therefore, given expression shows additive inverse property.

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3 years ago

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photoshop1234 [79]

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3 years ago

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aleksandrvk [35]

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3 years ago

What is the value of this expression when<br> d= 47 and f = 3?<br> 6 (d - f) +f

agasfer [191]

Answer:

267

Step-by-step explanation:

We are given the expression: 6 (d - f) +f

The value of the expression when d= 47 and f = 3 is :

6 (47 - 3) +3 = 6×(44) + 3 = 264 + 3 = 267

=267

7 0

2 years ago

3 regions are defined in the figure find the volume generated by rotating the given region about the specific line

anastassius [24]

The volume generated by rotating the given region $R_{3}$ about OC is $\frac{4}{g} \pi$

<h3>Washer method</h3>

Because the given region ( $R_{3}$ ) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

$y=2(x)^{\frac{1}{4} }$

$x=(\frac{y}{2} )^{4}$

$y=2x$

$x=\frac{y}{2}$

$\int\limits^a_b {\pi } \, (R_{o^{2} } - R_{i^{2} } ) dy$

$R_{o} = x = \frac{y}{2}$

$R_{i} = x= (\frac{y}{2}) ^{4}$

$a=0, b=2$

$v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} ) dy$

$v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }} ] dy$

$v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]$

$v=\pi [\frac{1}{4} \frac{y^{3} }{3} \int\limits^2_0 - \frac{1}{2^{8} } \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi$

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0

2 years ago