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Law Incorporation [45]
3 years ago
10

Given: angle 1 = angle 4 Prove: angle 2 = angle 3

Mathematics
1 answer:
natulia [17]3 years ago
3 0

\angle 1 = \angle 2 \qquad vertical angles

\angle 3 = \angle 4 \qquad vertical angles

\angle 1 = \angle 4 \qquad given

\angle 2 = \angle 3 \qquad transitivity

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STATE ALL OF THE MODULES THAT ARE INCLUDED IN DISCRETE MATHEMATICS.
serious [3.7K]

Module 1: set, relations, functions, numbers

Module 2: logic and boolean algebra

Module 3: combinatorics and probability

Module 4: graphs and trees

Module 5: induction and recursion

Module 6: grammars, languages and finite state machines.

4 0
3 years ago
The equation a = StartFraction one-half EndFraction left-parenthesis b 1 plus b 1 right-parenthesis.(b1 + b2)h can be used to de
aleksley [76]

Answer:

The equivalent expressions are:

b1=\frac{2a}{h}-b2

h=\frac{2a}{b1+b2}

Step-by-step explanation:

Given equation for finding area of a trapezoid:

a=\frac{1}{2}(b1+b2)h\\

where a represents area, h represents height and b1\ and\ b2 represents the base lengths of the trapezoid.

Evaluating h by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

2\times a=2\times\frac{1}{2}(b1+b2)h

2a=(b1+b2)h

Dividing both sides by b1+b2

\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}

\frac{2a}{b1+b2}=h

\therefore h=\frac{2a}{b1+b2}

Evaluating b1 by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

2\times a=2\times\frac{1}{2}(b1+b2)h

2a=(b1+b2)h

Dividing both sides by h

\frac{2a}{h}=\frac{(b1+b2)h}{h}

\frac{2a}{h}=b1+b2

Subtracting both sides by b2

\frac{2a}{h}-b2=b1+b2-b2

\frac{2a}{h}-b2=b1

\therefore b1=\frac{2a}{h}-b2

8 0
3 years ago
Read 2 more answers
Is (1, 4) a solution to the equation y = 7x?
VashaNatasha [74]

Answer:

No

Step-by-step explanation:

y=7x

4=7(1)

4=7

This is not a true statement.

4 0
4 years ago
Help I'm justing learning about this and I don't know what to start or do​
neonofarm [45]
It’s C!! don’t listen to the first answer. all you have to do it count how many zero’s there are
7 0
3 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
BigorU [14]
You have two 30-60-90 triangles, ADC and BDC.

The ratio of the lengths of the sides of a 30-60-90 triangle is

short leg : long leg : hypotenuse
     1        :  sqrt(3)  :        2

Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC

First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30

Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10

AB = AC - BC = 30 - 10 = 20
6 0
3 years ago
Read 2 more answers
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