To factor an expression, first you have to find the GCF or Greatest Common Factor of all of the pieces of the expression.
The GCF of 2y^2 and -4y is 2y
So, to factor this expression, we need to divide all of the pieces of the expression by the GCF.
2y(y-2)
2y^2 - 4y in completely factored form is 2y(y-2)
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
The equation describes a circle of radius 2 centered at (x, y) = (7, -8). In standard form, the equation would be
.. (x -7)^2 +(y +8)^2 = 4
A graph of it can be seen here. https://www.desmos.com/calculator/14zlfrtoa1
Answer: c = 9
Step-by-step explanation:
12-9=3+9=12
