The equation y=mx+b
Slope= m
y-intercept= b
y= 2x+0 so y=2x
Answer:
center of circle: (0,6)
radius: 4
the point (sqrt17,7) is NOT located on this circle. It is outside of the circle. This circle cuts off at (sqrt15,7), therefor (sqrt17,7) is not included
Hello there!
A positive slope is represented in a linear equation by a positive coefficient behind the x term. A positive slope means that the graph is on an increasing interval as x approaches +∞. In a more simple way, a positive slope means that the graph is going up from left to right.
A negative slope is represented in a linear equation by a negative coefficient behind the x term. A negative slope means that the graph is on a decreasing interval as x approaches +∞. In a more simple way, a negative slope means that the graph is going down from left to right.
The x intercept(s) of a graph are where the graph touches the x-axis. These are also known as the zero(s) OR solution(s) of the function.
The y intercept(s) of a graph are where the graph touches the y-axis.
I hope this helps!
Best wishes:)
The First is sec^2(x). Second is 2sec^2tanx. From that you get 2[2sec^2xtan^x+sec^4x]
12, or -12
12*12 = 144
-12*-12 = 144
