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3 years ago

I have an F in Math, I need to get this done, can someone help me?

Mathematics

2 answers:

musickatia [10]3 years ago

7 0

It cannot be a, b, or d so it has to be c

serg [7]3 years ago

5 0

Clearly, it cannot be A or D, since neither of those involve areas. They involved the length of something, whether the perimeter of the circle, or the length of the diameter. It can't be area of a circle either, because when you draw this out, it looks like a slice of cake. That means that the answer would be

C. Sector of a circle

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-1/2 (-6x + 3) plz helpppp

umka21 [38]

Answer:

-1/2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

(It’s a 6 not a 5) A-dot 1 B-dot 2 C-dot 3 D-dot 4

Taya2010 [7]

A- dot 1 . that’s the answer but it’s making me type 20 words.

8 0

3 years ago

8/15 divided by 1/3 reduce your answer

klio [65]

Here we can use fact than we can multiply fraction by inverse of fraction instead of dividing it.
Inverse of 1/3 is 3/1
Lets multiply it
$\frac{8}{15}* \frac{3}{1}= \frac{24}{15}= \frac{24:3}{15:3}= \frac{8}{5}=1 \frac{3}{5}$ - its our result

7 0

3 years ago

Question 16 (Essay Worth 7 points) Verify the identity. tan (x + π/2) = -cot x

Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

$\frac{sin(x+pi/2)}{cos(x+pi/2)}$

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

$\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)} = \frac{cos(x)}{cos(x+\pi/2) }$

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

$\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)$

6 0

3 years ago

Find 3x2 − y3 − y3 − z if x = 3, y = −2, and z = −5.

IceJOKER [234]

3x²-y³ - y³ - z if x = 3, y = -2, z = -5

Simply plug in all the values :)

3(3²) - (-2³) - (-2³) - (-5)

Simplify.

3(9) + 2³ + 2³ + 5

Simplify.

27 + 8 + 8 + 5

Simplify.

35 + 13

Simplify.

48

~Hope I helped!~

4 0

4 years ago