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Ratling [72]
4 years ago
6

Pure gold has a density of 19.32g/cm^3. You find a gold ring with a mass of 6g and a volume of 0.31cm^3.is this ring pure gold?

Chemistry
1 answer:
Dmitriy789 [7]4 years ago
4 0

Answer:

Yes, this ring is pure gold because when we divide the mass by the volume we get our density for the ring, which comes out to about 19.32.

Explanation:

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The chemical equations in model 1 contain the phase notations (s), (l), (g), and (aq). match each symbol with its meaning.
Sever21 [200]

Reaction equations contains symbols which show the physical state of the reactants and products.

<h3>What is a chemical equation:</h3>

A chemical equation is an expression that shows the interaction of reactants to yield products. Usually, symbols such as (s), (l), (g), and (aq) are used to show the state of the reactants and products.

The following are the respective meanings of these symbols;

  • (s) - solid
  • (l) - Liquid
  • (g) - gas
  • (aq) - dissolved in water

Learn more about reaction equations: brainly.com/question/1170557

8 0
2 years ago
A screw is an example of a modified 1 pulley 2 Wedge 3 inclined plane 4 wheel​
valentinak56 [21]

Answer: The answer would be D.

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8 0
2 years ago
If fluorine 20 undergoes beta decay , what will it become ?
e-lub [12.9K]
Fluorine 20 (F - Atomic number 9 and atomic mass 20). Firstly we need to know what is beta decay. Beta decay occurs when one neutron changes into a proton and an electron therefore the atomic mass will remain the same as even though we loose a neutron it is replaced by a proton, the atomic number is always raised by 1 when one beta decay occurs. The produced electron is shot out of the nucleus at an incredible speed. This speedy electron we call a beta particle.

Ok now the reaction.

 20       20        0
F  -> Ne    +     e
 9         10       -1

Remember the atomic number determines the nature of the element ( i.e what elemnt it is).
Hope this helps :).
7 0
3 years ago
HELP. NO FAKE ANSWERS. I WILL REPORT. I AM CONFUSED AND NEED HELP. FILL IN THE NOT FILLED BOXES POR FAVOR.
SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
       = 0.0075 moles × 1000/20
       = 0.375 M

7 0
3 years ago
HELPPPPPPPP <br> how many atoms in sodium hydrate
musickatia [10]
There are 4 atoms in sodium hydrate
5 0
3 years ago
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