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horsena [70]
3 years ago
6

PLEASE HELP ME ASAp!!!!!!

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

The area of the prism: 404 square feet.

Step-by-step explanation:

The idea in this exercise is to find the areas of all the geometric figures, and then add them all.

Notice that we have four consecutive rectangles, two smaller with dimension 6 ft by 8 ft and two larger with dimension 11 ft by 8 ft. Then, combined area of this four rectangles is

A_1 = 6*8 + 6*8 + 11*8+11*8 = 48+48+88+88 = 272.

For the other two rectangles, notice that their bases has the same length (11 ft). Their height can obtained using the characteristics of the prism. In this case must be 6 ft, the same length of the base of the previous smaller rectangles. The, the combined area of this rectangle is

A_2 = 6*11 +6*11 = 66 + 66 = 132.

Finally, adding those two area we get the area of the prism: 404 square feet.

alexandr1967 [171]3 years ago
6 0
The Surface area is
404ft
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Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

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