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erica [24]
3 years ago
8

Need help as soon as possible

Mathematics
1 answer:
zubka84 [21]3 years ago
4 0

If i did it right, your answer is 50.

-Seth

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4x−3=16=4(x−3)=16 <br> Do they have the same solution?
AnnZ [28]

Answer:

no

Step-by-step explanation:

4x -3 = 16

x=19/4

4(x-3) = 16: Distribute the number in the parenthesis with 4 and you get:

4x-12=16

x=7

4x-12=16 is not the same as 4x-3=16

Therefore they do not have the same solution.

5 0
3 years ago
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lesa saved 17,689 pennies lynn saved 1614 connie saved 176 pennies how many pennies did they save altogether
Goshia [24]
To find your answer you must add them all together :
17,689
1,614
+ 176
_________
19,479
5 0
3 years ago
What is the answer to the equation?<br><br> 1+1=_
iVinArrow [24]

Answer:2

Step-by-step explanation:

6 0
3 years ago
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A car can travel 150 miles on 4 gallons of petrol. How far can it travel on 6 gallons?
Ket [755]

Answer: The car can travel 225 miles on 6 gallons of petrol.

6 0
2 years ago
A company that produces dog food claims that its bags contain 11 kg of food. From
andriy [413]

By testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Given mean of 10.6 kg, population standard deviation of 0.6 and sample size of 25.

We are required to find whether the company is right in saying that their bags contain 11 kg of food.

First we have to make hypothesis.

H_{0}:μ≠11

H_{1}:μ=11

We have to use t statistic because the sample size is less than 30.

t=(X-μ)/s/\sqrt{n}

We will use s/\sqrt{n}=0.6 because we have already given population standard deviation of weights.

t=(11-10.6)/0.6

=0.4/0.6

=0.667

Degree of freedom=n-1

=25-1

=24

T critical at 0.05 with degree of freedom 24=2.0639

T critical at 0.05 with degree of freedom is greater than calculated t so we will accept the null hypothesis.It concludes that the bags donot contain 11 kg of food.

Hence by testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Learn more about t test at brainly.com/question/6589776

#SPJ1

3 0
1 year ago
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