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Lorico [155]
3 years ago
5

-3х + Зу = 9 2х — 7y = –14

Mathematics
1 answer:
Ratling [72]3 years ago
3 0

Answer:Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( −7 5 , 8 5 )

Equation Form:

x = − 7 5 , y = 8 5

Step-by-step explanation:

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Multiply.
Debora [2.8K]

6x^8−10x^2+8x^2

option C

hope it helps...!!!

6 0
1 year ago
Find the approximate volume of the figure below, composed of a cone, a cylinder, and a hemisphere. If necessary, round your answ
mixas84 [53]

Answer:

Volume of the solid = 480.42m³

Step-by-step explanation:

To sov this question, we'll have to break the solid into different shapes of solid to solve it easily.

Volume of a cylinder = πr²h

volume of a hemisphere = 4/3πr³

Volume of a cone = ⅓πr²h

π = 3.14

r = 3m

h(cylinder) = 11m

Slant height of cone = 3√(2)

Height of cone = ?

To find height of cone, we can use pythagorean theorem

a² = b² + c²

[ 3√(2)]² = 3² + c²

9*2 = 9 + c²

C² = 18 - 9

C = 9m

Height of the cone = 9m

Volume of a cylinder = πr²h

V = 3.14 * 3² * 11

V = 310.86m³

Volume of the cylnder = 310.86m³

Volume of the hemisphere = 4/3πr³

V = 3.14 * 3³

V = 84.78m³

Volume of the hemisphere = 84.78m³

Volume of the cone = ⅓πr²h

V = ⅓ * 3.14 * 3² * 9

V = 84.78

Volume of the cone = 84.78m³

Volume of the solid = volume of cone + volume of hemisphere + volume of cylinder

Volume of the solid = 84.78 + 84.78 + 310.86

Volume = 480.42m³

5 0
3 years ago
PLZ HELP I PROMISE I WILL GIVE BRAINLIEST!!!! ASAP
irga5000 [103]

Answer:

4c^{7}d^{13}

Step-by-step explanation:

(2cd^{4} )^{2} *(cd)^{5}

4c^{2}d^{8} *c^{5} d^{5}

4c^{7}d^{13}

4 0
3 years ago
If 1.6 cup of icing cover 2.3 of a cake then how much icing is need to cover the entire cake
Setler79 [48]
Mark me as brainliest! :)

1/6 * 3/2 = 1/4
5 0
2 years ago
Please help i don’t understand this
swat32

Similar polygons only differ by a scaling factor. In other words, two polygons are similar if one is the scaled version of the other.

In particular, this implies that the angles are preserved, and the correspondent sides are in proportion.

These two polygons are both rectangles, so the angles are preserved. We must check the sides, and we have to check if the smaller sides are in the same proportion as the bigger sides.

So, the two rectangles are similar if the following is true.

4\div 5 = 11\div 12

In any proportion, the product of the inner terms must be the same as the product of the outer terms:

4\cdot 12 = 5\cdot 11 \iff 48=55

This is clearly false, and thus the two rectangles are not similar.

5 0
2 years ago
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