The kids have to wait for 1 hour to get their bags.
<u>Step-by-step explanation:</u>
Given that,
A bus with kids and a truck with their bags started moving from the school to the camp at the same time.
- The speed of the bus was 60 mph.
- It took kids 3 hours to reach the camp.
<u>To find the distance traveled by the bus :</u>
⇒ Distance = Speed × Time
⇒ 60 × 3
⇒ 180 m
∴ The distance is 180 m.
<u>To find the time taken by the truck to reach the camp :</u>
- The speed of the truck was 45 mph.
- We found the distance as 180 m.
Time taken = distance / speed.
⇒ 180 / 45
⇒ 4 hours.
∴ The time taken by the truck to reach the camp is 4 hours.
<u>To find how long the kids have to wait for their bags :</u>
The time taken by the truck to reach the camp - the time it took for the kids to arrive.
⇒ 4 hours - 3 hours
⇒ 1 hour.
∴ The kids have to wait for 1 hour to get their bags.
Answer:
1261.68
Step-by-step explanation:
1350 = the increased watch price= 107% of the original
1350= 1.07x
1261.68224299
Check:
7% of 1261.68224299 is 88.317757
1261.68224299 + 88.317757 = 1349.9 = 1350
Round:
1261.68224299
To the penny= to the hundreth= 1261.68
Least to greatest would be 1/5 , 0.23 , and then 2.30%
#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack?
1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams.
You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..
4000grams/50snacks = 80 grams each snack.
#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?
215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams
So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348
0.348 is the difference.