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C: 0.012 mol.
<h3>Explanation</h3>Start with 0.0020 moles of iodate ions .
How many moles of iodine will be produced?
converts to
in the first reaction. The coefficient in front of
is three times the coefficient in front of
. In other words, each mole of
will produce three moles of
. 0.0020 moles of
will convert to 0.0060 moles of
.
How many moles of thiosulfate ions are required?
reacts with
in the second reaction. The coefficient in front of
is twice the coefficient in front of
. How many moles of
does each mole of
consume? Two. 0.0060 moles of
will be produced. As a result,
moles of
will be needed.
Answer:
a. The second run will be faster.
d. The second run has twice the surface area.
Explanation:
The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.
The area of the 10.0 cm³-sphere is:
The area of each 1.25 cm³-sphere is:
The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²
The ratio of 8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00
Since the surface area is doubled, the second run will be faster.