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Scorpion4ik [409]
3 years ago
10

Match the element to its oxidation number. Sulfur

Chemistry
2 answers:
AlexFokin [52]3 years ago
8 0

Answer:+6

Explanation:

shtirl [24]3 years ago
5 0
It’s oxidation number is +6
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An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12. W
EleoNora [17]
            
             H  H H H H H
              |   |   |   |   |   |
         H-C-C-C-C-C-C-H  
              |   |   |   |   |   | 
             H  H H H H H
This is the structural formula for C6H14. Every carbon atom in the molecule must be surrounded by four bonds. Hope this answers your question. 



8 0
2 years ago
Why does a pan of warm water eventually become the same temperature as the room it is in
rewona [7]
the room will either cool down or warm up the water until it is the same temperature as the room around it.
4 0
2 years ago
What is the number of electrons and protons can be seen in this atom?
pochemuha

Explanation:

the number of electrons = 8

and protons = 8 can be seen in this atom

8 0
3 years ago
Solid potassium chlorate decomposes upon heating to form
olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of  oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

V2 = 664.1052 ml

245.2   yielded 67.2 molar volume of oxygen

0.66411 will yield = \frac{245.2 * 0.66411}{67.2}  = 2.4232 g

percentage of potassium chlorate in the original mixture = \frac{2.4232 * 100}{7.44} = 32.6%

3 0
3 years ago
What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
alina1380 [7]

Mass of H₂ needed to react with O₂ : 1.092 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Reaction

O₂(g) + 2H₂(g) → 2H₂O(g)

mass of O₂ : 8.75 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{8.75}{32}=0.273

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

\tt \dfrac{2}{1}\times 0.273=0.546

Mass H₂ (MW=2 g/mol) :

\tt 0.546\times 2=1.092~g

4 0
2 years ago
Read 2 more answers
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