During combustion, chemical energy stored in fossil fuels is converted into KINETIC energy.
Answer:
D. 40 % increase
Step-by-step explanation:
r = k[A]²/[B]
The rate is inversely proportional to [B]. If [B] is doubled, the rate is halved.
We must double this rate to get back to the original.
The rate is directly proportional to [A]².
2 = [A]₂/[A]₁² Take the square root of each side
√2 = [A]₂/[A]₁ Multiply each side by [A]₁
[A]₂ = √2[A]₁
[A]₂ = 1.41[A]₁
We must increase [A] by 41 %.
Answer:
the narrator and the newsies
Since there is more energy added as heat rises, the particles disperse and have larger movements.
Answer is: <span>c. Fe</span>₃<span>O</span>₄<span>.
</span>ω(Fe) = 72,360%.
ω(O) = 100% - 72,36% = 27,64%.
For example, if we the mass of compound is 100 g:
m(Fe) = 72,36 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 72,36 g ÷ 55,85 g/mol.
n(Fe) = 1,296 mol.
n(O) = 27,64 g ÷ 16 g/mol.
n(O) = 1,727 mol.
n(Fe) : n(O) = 1,296 mol : 1,727 mol.
n(Fe) : n(O) = 1 : 1,33 or 3 : 4.