<span>B. ability of a substance to transfer energy </span>
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Answer:
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Answer:
Percent error = -22%
Explanation:
Given data:
Density of aluminium = 2.1,2.12 and 2.09 g/cm³
Accepted value of density of aluminium = 2.7 g.cm³
Percent error = ?
Solution:
First of all we will calculate the average of data measured by students.
Average value = 2.1 g/cm³ + 2.12 g/cm³+ 2.09 g/cm³ / 3
Average value = 6.31 g/cm³/ 3
Average value = 2.1 g/cm³
Now we will calculate the percent error.
Percent error = [ Measured value - accepted value / accepted value ]× 100
Percent error = [ 2.1 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ]× 100
Percent error = [-0.6/2.70 g/cm³ ] × 100
Percent error = -0.22 × 100
Percent error = -22%
<u>Ans: P = 22.5% and Cl = 77.5%</u>
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<u>Given:</u>
Total Mass of sample containing P and Cl = 50.51 g
Mass of P produced = 11.39 g
<u>To determine:</u>
Mass % of P and Cl
<u>Explanation:</u>
Mass % of a given element in a total mass is generally expressed as:
Mass % of element = [mass of element/total mass]*100
Here,
Total mass = mass of P + mass of Cl
mass of Cl = Total - mass of P = 50.51-11.39 = 39.12 g
% P = [11.39/50.51]*100 = 22.5%
%Cl = [39.12/50.51]*100 = 77.5%