HELP 1. What is the distance formula?

PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!In two or more complete sentences explain how you would set up and solve the following eq

olchik [2.2K]

Peter's account is 910-40x, and Marla's account is 470-2x. This is a system, so you must find the number that makes both equations end up with the same number. Basically trial and error. Here is what I did:

Let's try the number 10. 910-400=510 and 470-20=450. I need a higher number.

Let's try 13 next. 910-520=390 and 470-26=444. Now the number has to be lower.

Let's try 12. 910-480=430 and 470-24=446. Close, and a little lower.

11.5 is too low, and 11.7 is too high. 11.6 has Equation 1 at 446 and Equation 2 at 446.8. Very close!

It is somewhere around 11.6. I hope that this can give you a start in figuring it out, because I don't believe in giving the complete answer, because then you do not learn anything from it.

4 0

4 years ago

Read 2 more answers

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app

AfilCa [17]

Answer:

$Q(t) = 4.5(1.013)^{t}$

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

$Q(t) = Q(0)(1+r)^{t}$

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that $Q(0) = 4.5, r = 0.013$

So

$Q(t) = Q(0)(1+r)^{t}$

$Q(t) = 4.5(1.013)^{t}$

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

$Q(t) = 4.5(1.013)^{t}$

$Q(39) = 4.5(1.013)^{39} = 7.45$

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0

4 years ago

Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0

3 years ago

Tyee went shopping for a new video game because of a sale. The store was offering a 45% discount. If the price on the tag was p,

monitta

Answer:

It would be 0.45p.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Y-intercept of a line that has a slope of 2 and passes<br> through the point (4, 6).

tia_tia [17]

Answer:

Step-by-step explanation:

The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.

m = 2

(4, 6) ⇒ x₀ = 4, y₀ = 6

So, the point-slope form of equation:

y - 6 = 2(x - 4)

Changing to the slope-intercept form of the equation of the line (y = mx + b, where m is the slope and b is the y-intercept of the line):

y - 6 = 2x - 8 {add 6 to both sides}

y = 2x - 2 ⇒ b = -2

6 0

3 years ago