Answer:
Explanation:
The <em>purchase price</em> is what Janice invested for every share.
Since the stock was priced at $31.82 per share and she received a $1.11 dividend per share, her investment was:
- $31.82 - $1.11 = $30.71 per share ← answer
This price is the cost for Janice, over which she shall calculate their returns (gains or losses) on the future, when she sells the shares, for instance.
The total investment of Janice was the number of shares multipled by the purchase price:
- 40 shares × ($31.82 - $1.11)/ share
- 40 shares × ($30.71) / share = $1,228.40 (total investment)
Hummm... Its not normally reported that way. First you need to determine how many miles you are getting per gallon. A good estimate is that you will discharge 19.6 pounds of CO2 from burning 1 gallon of gasoline. This does not depend on the power or configuration of the engine. Of course if the car gets more miles per gallon of gasoline, you will get less CO2 per unit of service rendered (that is, less CO2 per mile traveled).
<span>Once you determine how many miles per gallon you are getting then divide that by 19.6 and that should give you the pounds of Carbon dioxide produced per mile. </span>
<span>The U.S. Department of Energy and the U.S. Environmental Protection Agency recently launched a new Fuel Economy Web Site designed to help the public factor energy efficiency into their car buying decisions. This site offers information on the connection between fuel economy, advanced technology, and the environment. </span>
First we calculate the mass of carbon,
hydrogen and oxygen.
Mass of Carbon;<span>
Molar mass of CO</span>₂ is 44.009g/mol and molar mass of C = 12.011 g/mol
<span>Mass of Carbon in 14.08g CO2</span>₂ = 12.011/44.009 x 14.08 = 3.84
<span>
Mass Hydrogen;
Molar mass H</span>₂O is 18.0015g/mol and molar mass of H is 1.008and H₂ = 2.016
<span>Mass Hydrogen in 4.32g of H</span>₂O = 2.016/18.0015 x 4.32 = 0.48
<span>
<span>Mass of Oxygen
= total mas of tartaric acid – (mass of carbon + mass of hydrogen) = 12.01 -
(3.84+0.48) = 7.69</span>
Now divide carbon, hydrogen and oxygen through
their respective atomic masses: </span>
<span>C = 3.84/12.011 = 0.32
<span>H = 0.48/1.008 = 0.48
<span>O = 7.69/15.999 = 0.48
Now divide by smallest: </span>
C = 0.32/0.32 = 1 </span>
H = 0.48/0.32 = 1.5
O = 0.48/0.32 = 1.5
multiply by 2 to get whole integers: </span>
C = 1 x 2 = 2
H= 1.5 x 2 = 3
<span>O= 1.5 x 2 = 3
<span>Thus, the Empirical formula of tartaric acid =
C</span></span>₂H₃O₃
One way can be forming an ionic bond
Second way can be forming covalent bond
And finally, the third way could be forming Co-ordinate bond
