Question

A proton in a linear accelerator has a de Broglie wavelength of 132 pm. What is the speed of the wavelength?

Answer 1

Answer:

The speed of wavelength is 3.0 ×10³ m/s.

Explanation:

Given data:

De Broglie wavelength = 132 pm (132×10⁻¹² m)

Speed of wavelength = ?

Solution:

Formula:

λ = h/mv

λ = wavelength

h = planck's constant

m = mass of proton

v = speed

now we will put the values in formula.

132×10⁻¹² m = 6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × v

v =  6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m

j = kg m²/s²

v = 6.63 ×10⁻³⁴ kg m²/s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m

v = 6.63 ×10⁻³⁴ kg m²/s / 220.44 ×10⁻³⁹ kg.m

v = 0.03×10⁵ m/s

v = 3.0 ×10³ m/s

The speed of wavelength is 3.0 ×10³ m/s.