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Tema [17]
3 years ago
14

PLEASEEE HELPPP MEEE

Chemistry
2 answers:
Brums [2.3K]3 years ago
8 0

Answer: H2O is the right answer

andrezito [222]3 years ago
4 0

Answer:

yes the one that is circled is correct

Explanation:

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An aqueous solution contains 0.23 M potassium hypochlorite.
Arturiano [62]

Answer:

0.22 mol HClO, 0.11mol HBr.

0.25mol NH₄Cl, 0.12 mol HCl

Explanation:

A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.

Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of <em>0.22 mol HClO  </em>will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, <em>0.11mol HBr</em> will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.

Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of <em>0.25mol NH₄Cl</em> will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of<em> 0.12 mol HCl</em>  will produce NH₄⁺. 0.25mol HCl consume all NH₃.

5 0
3 years ago
MgCI2 how many element ?
polet [3.4K]

Answer:

2 elements magnesium(Mg) and chlorine (Cl)

7 0
3 years ago
theres this really cute boy in my science class and i asked him if he wanted to be my lab partner and he said yes he doesn't tal
natita [175]
Make small talk and become his friend get to know him if he opens up he trust you and then you take it from there.
3 0
3 years ago
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How are oxidation-reduction reactions related to how you use energy?
Tems11 [23]

Answer:

In oxidation reduction reactions, one species gets reduced by taking on electron(s) and another species gets oxidized by losing electrons. They also flow by a wire

Explanation:

8 0
3 years ago
The number to the right of an element's symbol (ex. C-12) identifies the _____ of an isotope. A. atomic mass B. mass number C. a
OverLord2011 [107]

Answer:

Atomic Mass

Explanation:

it is also sometimes below the symbol of the element :)

7 0
3 years ago
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