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DENIUS [597]
2 years ago
15

Help c/8+5 = 24 a) 192 b) 3 c) 7 d) 152

Mathematics
2 answers:
SpyIntel [72]2 years ago
7 0

Answer:

c = 152

Step-by-step explanation:

c/8+5 = 24

Subtract 5 from each side

c/8+5-5 = 24-5

c/8 = 19

Multiply each side by 8

c/8*8 = 19*8

c =152

-Dominant- [34]2 years ago
5 0

Answer:

D. 152

Step-by-step explanation:

First, subtract 5 from both sides:

c/8 + 5 = 24

c/8 = 19

Multiply both sides by 8:

c = 152

So, the correct answer is D, 152

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2 cot^2t sin t - cot^2t = 0
Eduardwww [97]

2 cot²(<em>t </em>) sin(<em>t </em>) - cot²(<em>t </em>) = 0

cot²(<em>t </em>) (2 sin(<em>t </em>) - 1) = 0

cot²(<em>t </em>) = 0   <u>or</u>   2 sin(<em>t</em> ) - 1 = 0

cot(<em>t</em> ) = 0   <u>or</u>   sin(<em>t</em> ) = 1/2

cos(<em>t</em> ) / sin(<em>t</em> ) = 0   <u>or</u>   sin(<em>t</em> ) = 1/2

cos(<em>t</em> ) = 0   <u>or</u>   sin(<em>t</em> ) = 1/2

[<em>t</em> = cos⁻¹(0) + 2<em>nπ</em>   <u>or</u>   <em>t</em> = cos⁻¹(0) - <em>π</em> + 2<em>nπ</em>]

  <u>or</u>   [<em>t</em> = sin⁻¹(1/2) + 2<em>nπ</em>   <u>or</u>   <em>t</em> = <em>π</em> - sin⁻¹(1/2) + 2<em>nπ</em>]

(where <em>n</em> is any integer)

<em>t</em> = <em>π</em>/2 + 2<em>nπ</em>   <u>or</u>   <em>t</em> = -<em>π</em>/2 + 2<em>nπ</em>   <u>or</u>   <em>t</em> = <em>π</em>/6 + 2<em>nπ</em>   <u>or</u>   <em>t</em> = 5<em>π</em>/6 + 2<em>nπ</em>

Note that the first two families of solutions overlap and can be condensed, so that

<em>t</em> = <em>π</em>/2 + <em>nπ</em>   <u>or</u>   <em>t</em> = <em>π</em>/6 + 2<em>nπ</em>   <u>or</u>   <em>t</em> = 5<em>π</em>/6 + 2<em>nπ</em>

3 0
3 years ago
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