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Hatshy [7]
3 years ago
14

Please answer with SPEED!!!!!!!!!!!!!!!!!!!!!!!!!!! (3^4)*(2^3)

Mathematics
2 answers:
Alexxandr [17]3 years ago
8 0

<u><em>Answer: =648 *The answer must have positive sign.*</em></u>

Step-by-step explanation:

This question's it's about the order of operations. p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right.

do parenthesis first.

(3⁴)=3*3*3*3=81

81(2³)

(2³)=2*2*2=8

multiply left to right.

81*8=648

648/8=81

648/81=8

<u><em>=648</em></u>

Hope this helps!

Thanks!

Have a great day!

Svet_ta [14]3 years ago
4 0

(3^4)*(2^3)

81*8

648

Answer:  648

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The volume of a cone, V, is represented by , where r is the cone’s radius and h its height.
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3 years ago
a listing for a home for sale is shown as follows: “3/2/1 house for sale. price 140000” what does “3/2/1” mean
Inessa05 [86]

Answer:

A

Step-by-step explanation:

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5 0
2 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
X^2 - y^2 = 100
luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}

Now, substitute this value back into either of the equations to solve for x.

x+y=5\\x-\frac{15}{2}=5\\

Add 15/2 to both sides:

x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}

Now, find the difference:

x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20

8 0
2 years ago
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