Question

Ammonia (NH3) is a weak base that reacts with a strong acid to form the ammonium ion, NH4 . In the titration of 15.00 mL of an ammonia cleaner with 0.5000 M HCl, 42.6 mL of the titrant was required to reach the endpoint. What is the concentration of the NH3 in solution

Answer 1

Answer: The concentration of the $NH_3$ in solution is 1.42 M

Explanation:

According to neutralization law:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1$ = basicity of $HCl$ = 1

$n_2$ = acidity of $NH_3$ = 1

$M_1$ = concentration of $HCl$ = 0.5000 M

$M_2$ = concentration of $NH_3$  = ?

$V_1$ = volume of $HCl$ = 42.6 ml

$V_2$ = volume of $NH_3$ = 15.00 ml

Now put all the given values in the above law, we get:

$(1\times 0.5000\times 42.6)=(1\times M_1\times 15.00)$

By solving the terms, we get :

$M_1=1.42M$

Thus the concentration of the $NH_3$ in solution is 1.42 M