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3 years ago

if .00327 g of gas dissolves in .376 L of water at 876 torr what quantity of this gas will dissolve 759 torr ?

Chemistry

1 answer:

MAXImum [283]3 years ago

4 0

Answer:- Solubility of the gas at 759 torr is 0.00753 g/L.

Solution:- From given data, 0.00327 g of gas is soluble in 0.376 L of water at 876 torr.

Solubility of gas at 876 torr pressure is = 0.00327g/0.376L = 0.00869 g/L

Solubility of gases is directly proportional to the pressure. It means, grater is the pressure, more is the solubility of gases.

So, 0.00869/876 = X/759

Where, X is the solubility of the gas at 759 torr.

X = 0.00869(759)/876

X = 0.00753 g/L

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A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t

VashaNatasha [74]

Answer: $V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{P_1V_1T_2}{T_1P_2}$

where,

$P_1$ = initial pressure of gas = 101.3 kPa

$P_2$ = final pressure of gas = 94.6 kPa

$V_1$ = initial volume of gas = 20.0 ml

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $297K$

$T_2$ = final temperature of gas = $283K$

Now put all the given values in the above equation, we get the final volume of gas.

$V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

$V_2=20.4ml$

Thus the correct numerical setup for calculating the new volume is $\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

3 0

3 years ago

1. Long strands of DNA that contain lots of genes

sergeinik [125]

Answer: chromosome

Explanation: :)

4 0

3 years ago

Read 2 more answers

3.0 cm x 4.0 cm x 1.0 cm [?]cm^3

CaHeK987 [17]

Explanation:

Hi there!!

you asked to multiply these all right,

you can simply multiply it ,

=3cm × 4 cm × 1cm

= 12cm^2×1cm (4×3=12)

= 12cm^3 (12×1=12)

Therefore, theanswer is 12 cm^3.

Hope it helps..

4 0

3 years ago

(a) a 0.2 m potassium hydroxide solution is titrated with a 0.1 m nitric acid solution. (i) balanced equation: (ii)what would be

Stells [14]

$\text{KOH} (aq) + \text{HNO}_3 (aq) \to \text{KNO}_3 (aq) + \text{H}_2\text{O} (l)$

The solution shall contain only $\text{KNO}_3 (aq)$ (and water) at the equivalence point. Both potassium hydroxide and nitric acid exist as strong electrolytes. As a result, $\text{KNO}_3 (aq)$ , the salt derived from a reaction between the two species would undergo hydrolysis of a negligible extent. This neutralization reaction therefore be neutral at the equilibrium point.

The question states that the solution is "titrated with a ... nitric acid solution" indicating that $\text{HNO}_3$ is added to the initially-basic solution. PH value of the solution would keep decreasing as the volume of the acid added increases. The final solution would be acidic as it contains not only water and $\text{KNO}_3 (aq)$ , but some $\text{HNO}_3$ as well. Bromothymol blue would therefore demonstrates a yellow color, the color it present in an acidic solution, at the end of the titration.

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3 years ago

Which is the correct complete ionic equation for the reaction of

cricket20 [7]

Answer:

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

Explanation:

The equation is given as;

2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)

In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.

This is given as;

2H+ + 2Cl- + Zn(s) --> H2(g) + Zn2+ + 2Cl-

The correct option is;

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

8 0

2 years ago