1. Constellations are group of <u>stars</u> that form pattems in the night sky
2. Ursa Major, Cassiopeia, and Orion are some common <u>constellations</u><u>.</u>
3. Stars are used to tell <u>directions</u> and time, predict weather, and to serve as birth sign.
Explanation:
The absolute temperature is the lowest possible temperature in the universe. At this temperature, all atoms become motionless and cease to move.
The value of the absolute zero is pegged at -273.16°C.
- It is the lowest limit of the coldness of a body.
- Nothing can be colder than a body at absolute temperature.
- Many researches are underway to take advantage of this temperature value for scientific purpose.
- Thermodynamically, all process stops at this temperature.
- When a body is brought close a body at absolute zero, it can suffer cryogenic burn due to heat transfer.
Answer:
Orbital, in chemistry and physics, a mathematical expression, called a wave function, that describes properties characteristic of no more than two electrons in the vicinity of an atomic nucleus or of a system of nuclei as in a molecule. ... A 1s electron occupies the energy level nearest the nucleus.
Explanation:
Answer:
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
Where,
is the enthalpy change
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of object = 36.2 g
Specific heat = 12.5 J/g°C
So,
Answer:
The freezing point of chloroform (CHCl₃) in presence of benzene = - 64.252 °C.
Explanation:
- We can solve this problem using the relation:
ΔTf = Kf.m,
Where, ΔTf is the elevation of freezing point,
Kf is the freezing point depression constant <em>(Kf of chloroform = 4.7 °C/m)</em>,
m is the molality of the solution.
- We can get the molality of benzene from the relation:
m = (mass / molar mass) solute (benzene) x (1000 / mass of solvent (CHCl₃))
m = (1.25 g / 78.11 g/mol) x (1000 / 100.0 g) = 0.160 m.
ΔTf = Kf.m = (4.70 °C/m) (0.160 m) = 0.752 °C.
∴ The freezing point in presence of benzene = The freezing point of pure CHCl₃ - ΔTf = - 63.50 °C – 0.752 °C = - 64.252 °C.
