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Reil [10]
3 years ago
8

Why does a person's heart rate increase during exercise?

Chemistry
2 answers:
vagabundo [1.1K]3 years ago
7 0
More oxygen is needed
ludmilkaskok [199]3 years ago
5 0
The answer is 2 more oxygen is needed
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1s2 2s2 2p6 3s2 3p6 is the electron configuration for
kvasek [131]

Answer: The electron configuration is for the element Argon

Explanation: 3p6 is all the way on the right side of the periodic table in the third row or period

3 0
3 years ago
Read 2 more answers
Select the correct answer.
givi [52]

Answer:

{1s^2 2s^2 2p^6} 3s^2 3p^4

{Ne}3s^2 3p^4

Explanation:

i didnt understand the rest of that but this is the e- configuration on top and the bottom is noble gas configuration

6 0
3 years ago
Mercury has an atomic mass of 200.59 amu. calculate the mass of 3.0 x 10^10 atoms
Licemer1 [7]
To determine mass of the given number of atoms of mercury, we need a factor that would relate the number of atoms to number of moles. In this case, we use the Avogadro's number. It is a <span>number that represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. The number of units could be atoms, molecules, ions or electrons. To convert into mass, we use the given amu of mercury since it is equal to grams per mole. We calculate as follows:

</span>3.0 x 10^10 atoms ( 1 mol / 6.022 x 10^23 atoms ) ( 200.59 g / 1 mol ) = 9.99x10^-12 g Hg
5 0
3 years ago
What statement best describes an independent variable?
Rzqust [24]
The answer is C. The independent variable is the factor that is changed by the experimenter and impacts the dependent variable.
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A solid forms when the average energy of a substance's particles
Dahasolnce [82]
<span>Matter is composed of particles that have kinetic energy. Particles with greater kinetic energy tend form liquids or gases due to increased rates of activity of the particles. Particles with lower energy tend to form solids. So, a solid forms when the average energy of a substance's particles decreases.</span>
4 0
3 years ago
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