Give the name of the following molecule. A compound with a total of seven carbons with a double bond and the rest single bonds.
There is a chain of four carbons along the bottom with a double bond between the third and fourth carbon when counting from left to right. There is a propyl group branching off of the third carbon from the left.
2 answers:
Answer:
2-ethyl-pentene.
Explanation:
Hello,
In this case, following the given indications, the molecule is shown of the attached picture. Thus, the double bond is placed as well as the propyl radical. In such a way, the resulting molecule is 2-ethyl-pentene since the longest chain has five carbons and at the second carbon there is an ethyl radical. Moreover, the double bond makes the molecule an alkene, finishing with "ene".
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The rate of disappearance of chlorine gas : 0.2 mol/dm³
<h3>Further explanation</h3>The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
For reaction :
The rate reaction :
Reaction for formation CCl₄ :
<em>CH₄+4Cl₂⇒CCl₄+4HCl</em>
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From equation, rate of reaction = rate of formation CCl₄ = 0.05 mol/dm³
Rate of formation of CCl₄ = reaction rate x coefficient of CCCl₄
0.05 mol/dm³ = reaction rate x 1⇒reaction rate = 0.05 mol/dm³
The rate of disappearance of chlorine gas (Cl₂) :
Rate of disappearance of Cl₂ = reaction rate x coefficient of Cl₂
Rate of disappearance of Cl₂ = 0.05 x 4 = 0.2 mol/dm³