Give the name of the following molecule. A compound with a total of seven carbons with a double bond and the rest single bonds.
There is a chain of four carbons along the bottom with a double bond between the third and fourth carbon when counting from left to right. There is a propyl group branching off of the third carbon from the left.
2 answers:
Answer:
2-ethyl-pentene.
Explanation:
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In this case, following the given indications, the molecule is shown of the attached picture. Thus, the double bond is placed as well as the propyl radical. In such a way, the resulting molecule is 2-ethyl-pentene since the longest chain has five carbons and at the second carbon there is an ethyl radical. Moreover, the double bond makes the molecule an alkene, finishing with "ene".
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