The temperature of their surroundings
Answer:
The root mean square speed of O2 gas molecules is
<u>519.01 m/s</u>
<u></u>
Explanation:
The root mean square velocity :



Molar mass , M
For He = 4 g/mol
For O2 = 2 x 16 = 32 g/mol
O2 = 32/1000 = 0.032 Kg/mol
First calculate the temperature at which the K.E of He is 4310J/mol
K.E of He =


K.E of He = 4310 J/mol


<u>Now , Use Vrms to calculate the velocity of O2</u>




Answer: 3.4 atm
Explanation:
Given that:
Volume of gas V = 5L
(since 1 liter = 1dm3
5L = 5dm3)
Temperature T = 0°C
Convert Celsius to Kelvin
(0°C + 273 = 273K)
Pressure P = ?
Number of moles of gas n = 0.75 moles
Note that Molar gas constant R is a constant with a value of 0.0821 atm dm3 K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 5dm3 = 0.75 moles x (0.0821 atm dm3 K-1 mol-1 x 273K)
p x 5dm3 = 16.8 atm dm3
p = (16.8 atm dm3 / 5dm3)
p = 3.4 atm
Thus, a pressure of 3.4 atm is exerted by the gas.
Answer:
E - Atomic mass is calculated by weighted atomic average using all the isotope data available.
G - Mass number is equal to the sum of protons and electrons in an atom.
Explanation:
Take an element

- Mass no is 25 and atomic no is 12.