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2 years ago

A bowling ball and basketball collide, what direction do they go and how is energy transferred?

Chemistry

1 answer:

olga nikolaevna [1]2 years ago

8 0

Answer:

When the batter hits the ball, there is a force applied, and energy is transferred. The ball will move in the direction the force is pushing it. If two objects collide, energy will be transferred between both, and there will be a change in motion.

Explanation:

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Two examples of energy transformations are shown.

erastova [34]

The energy transformations are similar because they result into radiant energy.

As for the lamp, Electrical energy is transformed into light when the filament

or mercury vapor glows on passage of current.

The fire- chemical energy is turned to light energy during the combustion of carbon. Both products comprise of ultraviolet radiation which is a form of radiant energy.

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3 years ago

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How many molecules of nitrogen gas are in 22.4 L?

Serhud [2]

The answer is letter (B).

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3 years ago

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A 256 mL sample of HCl gas is in a flask where it exerts a force (pressure) of 67.5 mmHg. What is the pressure of the gas if it

Effectus [21]

Answer:

The pressure in the new flask would be $128\; \rm mmHg$ if the $\rm HCl$ here acts like an ideal gas.

Explanation:

Assume that the $\rm HCl$ sample here acts like an ideal gas. By Boyle's Law, the pressure $P$ of the gas should be inversely proportional to its volume $V$ .

For example, let the initial volume and pressure of the sample be $V_1$ and $P_1$ . The new volume $V_2$ and pressure $P_2$ of this sample shall satisfy the equation: $P_1 \cdot V_1 =P_2 \cdot V_2$ .

In this question,

The initial volume of the gas is $V_1= 256\; \rm mL$ .
The initial pressure of the gas is $P_1 = 67.5\; \rm mmHg$ .
The new volume of the gas is $V_2 = 135\; \rm mL$ .

The goal is to find the new pressure of this gas, $P_2$ .

Assume that this sample is indeed an ideal gas. Then the equation $P_1 \cdot V_1 =P_2 \cdot V_2$ should still hold. Rearrange the equation to separate the unknown, $P_2$ . Note: make sure that the units for $V_1$ and $V_2$ are the same before evaluating. That way, the unit of

$\begin{aligned} & P_2\\ &= \frac{P_1 \cdot V_1}{V_2} \\ &= \frac{256\; \rm mL \times 67.5\; \rm mmHg}{135\; \rm mL} \\ & \approx 128\; \rm mmHg\end{aligned}$ .

3 0

3 years ago

878 kilograms to milligrams ( 8.78 E 8)

sammy [17]

K stands for thousands
1 k = 1000
1 milli = 0.001
covert 878kg to g
878 x 1000=878000 g or (8.78^5)
convert g to mg
878000 / 0.001 =878,000,000
=8.78^8
^ or E means power of

4 0

3 years ago

What is the frequency of a photon having an energy of 4.91 × 10–17 ? (c = 3.00 × 108 m/s, h = 6.63 × 10–34 J · s)

AlexFokin [52]

Answer:

The frequency of the photon is 7.41*10¹⁶ Hz

Explanation:

Planck states that light is made up of photons, whose energy is directly proportional to the frequency of radiation, according to a constant of proportionality, h, which is called Planck's constant. This is expressed by:

E = h*v

where E is the energy, h the Planck constant (whose value is 6.63*10⁻³⁴ J.s) and v the frequency (Hz or s⁻¹).

So the frequency will be:

$v=\frac{E}{h}$

Being E= 4.91*10⁻¹⁷ J and replacing:

$v=\frac{4.91*10^{-17} J}{6.63*10^{-34} J.s}$

You can get:

v= 7.41*10¹⁶ $\frac{1}{s}$ = 7.41*10¹⁶ Hz

The frequency of the photon is 7.41*10¹⁶ Hz

4 0

3 years ago